SQL，如何查询成绩连续3次上升的同学？

标签：https   net   order by   --   join   inner   ted   art   row   

-- 1.连续3次成绩上升
with t as
(select id,
StudentName,
Score,
row_number() over(partition by StudentName order by id desc) ‘rn‘
from #t)
select distinct a.id,a.StudentName
from t a
inner join t b on a.StudentName=b.StudentName
inner join t c on a.StudentName=c.StudentName
where a.rn=1 and b.rn=2 and c.rn=3
and a.Score>b.Score and b.Score>c.Score

/*
id StudentName
----------- -----------
34 李同学
38 王同学

(2 row(s) affected)
*/

-- 2.连续3次成绩下降
with t as
(select id,
StudentName,
Score,
row_number() over(partition by StudentName order by id desc) ‘rn‘
from #t)
select distinct a.id,a.StudentName
from t a
inner join t b on a.StudentName=b.StudentName
inner join t c on a.StudentName=c.StudentName
where a.rn=1 and b.rn=2 and c.rn=3
and a.Score<b.Score and b.Score<c.Score

/*
id StudentName
----------- -----------
35 赵同学

(1 row(s) affected)
*/

摘自CSDN问答，问答网址：https://bbs.csdn.net/topics/391059033

SQL，如何查询成绩连续3次上升的同学？

标签：https   net   order by   --   join   inner   ted   art   row   

原文地址：https://www.cnblogs.com/lumingprince/p/9798740.html