POJ 2367 Genealogical tree 拓扑排序入门题

#include<stdio.h>
#include<iostream>
#include<math.h>
#include<string.h>
#include<set>
#include<map>
#include<list>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long LL;
int mon1[13]= {0,31,28,31,30,31,30,31,31,30,31,30,31};
int mon2[13]= {0,31,29,31,30,31,30,31,31,30,31,30,31};
int dir[4][2]= {{0,1},{0,-1},{1,0},{-1,0}};

int getval()
{
    int ret(0);
    char c;
    while((c=getchar())==‘ ‘||c==‘\n‘||c==‘\r‘);
    ret=c-‘0‘;
    while((c=getchar())!=‘ ‘&&c!=‘\n‘&&c!=‘\r‘)
        ret=ret*10+c-‘0‘;
    return ret;
}

#define max_v 105
priority_queue<int,vector<int>,greater<int> > q;
int indegree[max_v];
int G[max_v][max_v];
int n,m;
void inittp()
{
    for(int i=1;i<=n;i++)
        if(indegree[i]==0)
            q.push(i);//入度为0的点放入优先队列，优先队列是为了考虑字典序输出
}
void tpsort()
{
    int temp;
    int c=1;
    while(!q.empty())
    {
        temp=q.top();
        q.pop();
        if(c!=n)
        {
            printf("%d ",temp);
            c++;
        }else
        {
            printf("%d\n",temp);
        }
        for(int i=1;i<=n;i++)
        {
            if(G[temp][i])//存在边
            {
                indegree[i]--;//i点入度--
                if(indegree[i]==0)//若入度为0则放入队列
                    q.push(i);
            }
        }
    }
}
int main()
{
    int x;
    while(~scanf("%d",&n))
    {
        memset(indegree,0,sizeof(indegree));
        memset(G,0,sizeof(G));
        for(int i=1;i<=n;i++)
        {
            while(1)
            {
                scanf("%d",&x);
                if(x==0)
                    break;
                if(G[i][x]==0)//防止重边增加入度
                {
                    G[i][x]=1;
                    indegree[x]++;
                }
            }
        }
        inittp();
        tpsort();
    }
    return 0;
}