标签:mod vector dex div cto [] col ack size_t
//求解复数组 中模较大的N个数 void fianN_Complex(Complex outVec[], int& len, std::vector<int>& index,int N) // Complex (&outVec)[512] 数组引用 单纯数组做参数退化为指针 { std::vector<double> modulus; for (size_t i = 0; i < len; i++) { double temp; temp=sqrt(outVec[i].im*outVec[i].im + outVec[i].rl*outVec[i].rl); modulus.push_back(temp); } if (index.size()<N) { if (index.size()!=0) { for (size_t i = 0; i < index.size(); i++) { modulus[index[i]] = 0; } } int indextemp = 0; for (size_t j = 0; j < modulus.size() - 1; j++) { if (modulus[j]>modulus[j + 1]) { double temp = modulus[j]; modulus[j] = modulus[j + 1]; modulus[j + 1] = temp; } else { indextemp = j + 1; } } index.push_back(indextemp); } }
标签:mod vector dex div cto [] col ack size_t
原文地址:https://www.cnblogs.com/lovebay/p/9842262.html