标签：col turn python pytho lse else for nbsp pre
def aa(nums,n): for i in range(n): if i ==nums[i]: i +=1 else: return i print(aa([0,1,2,3,4,5,7],8))
剑指offer python版 0到n-1中缺失的数字
原文地址：https://www.cnblogs.com/xzm123/p/9869226.html
