二叉树的简单实现--数据结构与算法纪录片第二记

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　　这几天状态不好看不下去，所以停了一下。今天把二叉树的实现写了一下，把其中的原理也重新理解了一遍。

package tree.bstree;

/**
 * @Description: TODO
 * @Auther: Zhang
 * @Date: 2018/11/5 16:34
 */
public class BSTNode<T extends Comparable<T>> {
    private T key;
    private BSTNode<T> parentNode;
    private BSTNode<T> leftChildrenNode;
    private BSTNode<T> rightChildrenNode;

    public BSTNode(T key) {
        this.key = key;
        parentNode = leftChildrenNode = rightChildrenNode = null;
    }

    public BSTNode(T key, BSTNode<T> parentNode, BSTNode<T> leftChildrenNode, BSTNode<T> rightChildrenNode) {
        this.key = key;
        this.parentNode = parentNode;
        this.leftChildrenNode = leftChildrenNode;
        this.rightChildrenNode = rightChildrenNode;
    }

    public T getKey() {
        return key;
    }

    public void setKey(T key) {
        this.key = key;
    }

    public BSTNode<T> getParentNode() {
        return parentNode;
    }

    public void setParentNode(BSTNode<T> parentNode) {
        this.parentNode = parentNode;
    }

    public BSTNode<T> getLeftChildrenNode() {
        return leftChildrenNode;
    }

    public void setLeftChildrenNode(BSTNode<T> leftChildrenNode) {
        this.leftChildrenNode = leftChildrenNode;
    }

    public BSTNode<T> getRightChildrenNode() {
        return rightChildrenNode;
    }

    public void setRightChildrenNode(BSTNode<T> rightChildrenNode) {
        this.rightChildrenNode = rightChildrenNode;
    }
}

package tree.bstree;

/**
 * @Description: TODO
 * @Auther: Zhang
 * @Date: 2018/11/5 16:33
 */
public class BSTree<T extends Comparable<T>> {

    private BSTNode<T> rootNode;

    public BSTree() {
        rootNode = null;
    }

    public BSTree(BSTNode<T> node) {
        rootNode = node;
    }

    //查找最大节点
    private BSTNode<T> maxNode(BSTNode<T> bstNode) {
        if (bstNode == null) {
            return bstNode;
        }
        while (bstNode.getRightChildrenNode() != null) {
            bstNode = bstNode.getRightChildrenNode();
        }
        return bstNode;
    }

    public BSTNode<T> maxNode() {
        return this.maxNode(rootNode);
    }

    //查找最小节点
    private BSTNode<T> minNode(BSTNode bstNode) {
        if (bstNode == null) {
            return bstNode;
        }
        while (bstNode.getLeftChildrenNode() != null) {
            bstNode = bstNode.getLeftChildrenNode();
        }
        return bstNode;
    }

    public BSTNode<T> minNode() {
        return this.minNode(rootNode);
    }

    //插入节点
    private void insert(BSTNode<T> bstNode) {
        int compareResult;
        BSTNode<T> parent = null;
        BSTNode<T> current = rootNode;

        //如果树为空，该节点为根节点
        if (rootNode == null) {
            rootNode = bstNode;
            return;
        }

        //数不为空，判断节点的位置
        while (current != null) {
            parent = current;
            compareResult = bstNode.getKey().compareTo(current.getKey());
            if (compareResult == 0) {
                System.out.println("该节点已存在树中");
                return;
            }
            if (compareResult < 0) {
                current = current.getLeftChildrenNode();
            } else {
                current = current.getRightChildrenNode();
            }
        }

        //将节点插入到树中
        bstNode.setParentNode(parent);
        compareResult = bstNode.getKey().compareTo(parent.getKey());
        if (compareResult < 0) {
            parent.setLeftChildrenNode(bstNode);
        } else {
            parent.setRightChildrenNode(bstNode);
        }
    }

    public void insert(T key) {
        BSTNode<T> bstNode = new BSTNode<>(key);
        this.insert(bstNode);
    }

    //删除节点
    private void delete(T key, BSTree<T> bsTree) {
        BSTNode<T> bstNode = this.find(key);
        if (bstNode == null) {
            System.out.println("没有找到该节点");
        }
        BSTNode<T> parent = bstNode.getParentNode();
        int comp = bstNode.getKey().compareTo(parent.getKey());
        //如果节点没有孩子节点
        if (bstNode.getLeftChildrenNode() == null && bstNode.getRightChildrenNode() == null) {
            if (comp > 0) {
                parent.setRightChildrenNode(null);
            } else {
                parent.setLeftChildrenNode(null);
            }
            return;
        }

        //如果该节点只有左子树或者该节点只有右子树
        //只有左子树
        if (bstNode.getLeftChildrenNode() != null && bstNode.getRightChildrenNode() == null) {
            if (comp > 0) {
                parent.setRightChildrenNode(bstNode.getLeftChildrenNode());
            } else {
                parent.setLeftChildrenNode(bstNode.getLeftChildrenNode());
            }
            return;
        }

        //只有右子树
        if (bstNode.getRightChildrenNode() != null && bstNode.getLeftChildrenNode() == null) {
            if (comp > 0) {
                parent.setRightChildrenNode(bstNode.getRightChildrenNode());
            } else {
                parent.setLeftChildrenNode(bstNode.getRightChildrenNode());
            }
            return;
        }

        //既有左子树又有右子树
        if (bstNode.getLeftChildrenNode() != null && bstNode.getRightChildrenNode() != null) {
            BSTNode<T> newNode = minNode(bstNode.getRightChildrenNode());
            if (bstNode.getRightChildrenNode() == newNode) {
                newNode.setRightChildrenNode(null);
            } else {
                parent.setRightChildrenNode(newNode);
                newNode.setLeftChildrenNode(bstNode.getLeftChildrenNode());
                newNode.setRightChildrenNode(bstNode.getRightChildrenNode());
            }
            if (comp > 0) {
                parent.setRightChildrenNode(newNode);
            } else {
                parent.setLeftChildrenNode(newNode);
            }
        }
    }

    public void delete(T key) {
        delete(key, this);
    }

    //查找节点
    private BSTNode<T> find(T key, BSTree<T> bsTree) {
        int comp;
        BSTNode<T> current = bsTree.rootNode;
        comp = key.compareTo(current.getKey());
        while (comp != 0) {
            if (comp > 0) {
                current = current.getRightChildrenNode();
            } else {
                current = current.getLeftChildrenNode();
            }
            if (current == null) {
                return current;
            }
            comp = key.compareTo(current.getKey());
        }
        return current;
    }

    public BSTNode<T> find(T key) {
        BSTNode bstNode = this.find(key, this);
        if (bstNode == null) {
            System.out.println("没有找到该节点");
        }
        return bstNode;
    }

    //前序遍历
    private void preOrder(BSTNode<T> bstNode) {
        if (bstNode != null) {
            System.out.println("key is : " + bstNode.getKey());
            preOrder(bstNode.getLeftChildrenNode());
            preOrder(bstNode.getRightChildrenNode());
        } else {
            return;
        }

    }

    public void preOrder() {
        System.out.println("前序遍历: ");
        this.preOrder(rootNode);
    }

    //中序遍历
    private void midOrder(BSTNode<T> bstNode) {
        if (bstNode != null) {
            midOrder(bstNode.getLeftChildrenNode());
            System.out.println("key is : " + bstNode.getKey());
            midOrder(bstNode.getRightChildrenNode());
        } else {
            return;
        }
    }

    public void midOrder() {
        System.out.println("中序遍历: ");
        this.midOrder(rootNode);
    }

    //后序遍历
    private void postOrder(BSTNode<T> bstNode) {
        if (bstNode != null) {
            postOrder(bstNode.getLeftChildrenNode());
            postOrder(bstNode.getRightChildrenNode());
            System.out.println("key is : " + bstNode.getKey());
        } else {
            return;
        }
    }

    public void postOrder() {
        System.out.println("后序遍历: ");
        this.postOrder(rootNode);
    }

    //前驱节点
    private BSTNode<T> predecessor(BSTNode<T> bstNode) {
        //如果存在左孩子，则前驱为最大左孩子
        if (bstNode.getLeftChildrenNode() != null) {
            return maxNode(bstNode.getLeftChildrenNode());
        }
        //不存在左孩子：如果该节点是其父节点的右孩子，则前驱节点为该节点的父节点
        //不存在左孩子：如果该节点是其父节点的左孩子，则往上查找最低父节点，该节点必须是其父节点的左孩子
        BSTNode<T> parent = bstNode.getParentNode();
        while (parent != null && parent.getLeftChildrenNode() == bstNode) {
            bstNode = parent;
            parent = bstNode.getParentNode();
        }
        return parent;
    }

    public BSTNode<T> predecessor(T key) {
        BSTNode<T> bstNode = this.find(key);
        if (bstNode == null) {
            return null;
        }else {
            return predecessor(bstNode);
        }
    }

    //后继节点
    private BSTNode<T> successor(BSTNode<T> bstNode) {
        //如果存在右孩子，则为右子树中的最小值
        if (bstNode.getRightChildrenNode() != null) {
            return minNode(bstNode.getRightChildrenNode());
        }

        //不存在右孩子：该节点为父节点的右节点，则后继节点为父节点
        //不存在右孩子：该节点为父节点的左节点，则往上查找最低的父节点且该节点为父节点的左节点
        BSTNode<T> parent = bstNode.getParentNode();
        while (parent != null && parent.getRightChildrenNode() == bstNode) {
            bstNode = parent;
            parent = bstNode.getParentNode();
        }
        return parent;
    }

    public BSTNode<T> successor(T key) {
        BSTNode<T> node;
        BSTNode<T> bstNode = find(key);
        if (bstNode == null) {
            return null;
        }else {
            return successor(bstNode);
        }
    }

}

package tree.bstree;

/**
 * @Description: TODO
 * @Auther: Zhang
 * @Date: 2018/11/5 18:15
 */
public class MainTest {
    public static void main(String[] args) {
        BSTNode<Integer> bstNode = new BSTNode<>(5);
        BSTree<Integer> bsTree = new BSTree<>(bstNode);
        bsTree.insert(4);
        bsTree.insert(2);
        bsTree.insert(9);
        bsTree.find(222);
        bsTree.insert(3);
        bsTree.delete(2);
        bsTree.insert(33);
        bsTree.insert(2);
        bsTree.preOrder();
        bsTree.midOrder();
        bsTree.postOrder();
        if (bsTree.predecessor(32)!=null){
            System.out.println(bsTree.predecessor(32).getKey());
        }
        System.out.println(bsTree.predecessor(33).getKey());
        System.out.println(bsTree.successor(3).getKey());

    }
}

二叉树的简单实现--数据结构与算法纪录片第二记

标签：current   lse   纪录片   des   turn   script   private   compare   []   

原文地址：https://www.cnblogs.com/qugemingzihaonan13/p/9914351.html