本文参考自http://blog.csdn.net/fhwbj/article/details/3267787
在使用Hibernate时,我们有时可能需要根据实体类获得数据库表的信息,上面的那个链接的内容已经给出了模版,不过使用Hibernate4时,如果获得的PersistentClass一直为null,可以试着采用下面的方式初始化Configuration
if (configuration == null) { configuration = new Configuration().configure(); configuration.buildSessionFactory(); }下面进入正题,在Hibernate和Spring集成时,如果我们是在Spring的配置文件中配置的Hibernate,即没有hibernate.cfg.xml文件(上面的方法必须要有此文件),那么我们又该如何获得Configuration呢?其实我们可以根据是Spring中配置的sessionFactory来获得Configuration对象,下面是具体的代码实现
HiberanteConfigurationUtil类 (映射工具类)
这里需要注意的是:
1.在取sessionFactory时要加上&号,原因可以看一下http://blog.csdn.net/zhangjk1993/article/details/40017583
2.这里采用的xml文件做的映射,要保证实体类名和对应的映射文件名一致
package util; import java.util.Iterator; import org.hibernate.cfg.Configuration; import org.hibernate.mapping.Column; import org.hibernate.mapping.PersistentClass; import org.hibernate.mapping.Property; import org.springframework.beans.BeansException; import org.springframework.context.ApplicationContext; import org.springframework.context.ApplicationContextAware; import org.springframework.orm.hibernate4.LocalSessionFactoryBean; /** * 根据实体类得到对应的表名、主键名、字段名(与Spring集成) * 这里使用xml文件配置的映射,需要保证实体类名与对应映射文件名一致,即User.java与User.hbm.xml * </p> * 这里使用继承ApplicationContextAware的方式来获得ApplicationContext, * 因此需要在Spring配置文件中配置一下该类,才能自动注入ApplicationContext对象 * * <bean class="util.HibernateConfigurationUtil"/> */ public class HibernateConfigurationUtil implements ApplicationContextAware { private static ApplicationContext applicationContext; private static Configuration configuration; public static Configuration getConfiguration() { if (configuration == null) { // 取sessionFactory的时候要加上& LocalSessionFactoryBean factory = (LocalSessionFactoryBean) applicationContext .getBean("&sessionFactory"); configuration = factory.getConfiguration(); } return configuration; } private static <T> PersistentClass getPersistentClass(Class<T> clazz) { synchronized (HibernateConfigurationUtil.class) { PersistentClass pc = getConfiguration().getClassMapping( clazz.getSimpleName()); if (pc == null) { configuration = configuration.addClass(clazz); pc = configuration.getClassMapping(clazz.getName()); } return pc; } } /** * 获得实体类对应的表名 * * @param clazz * 实体类的Class对象 * @return 表名 */ public static <T> String getTableName(Class<T> clazz) { return getPersistentClass(clazz).getTable().getName(); } /** * 获得实体类对应表的主键字段名称 * * @param clazz * 实体类的Class对象 * @return 主键字段名称 */ public static <T> String getPKColumnName(Class<T> clazz) { return getPersistentClass(clazz).getTable().getPrimaryKey() .getColumn(0).getName(); } /** * 获得类属性对应的字段名 * * @param clazz * 实体类的Class对象 * @param propertyName * 实体类的属性名 * @return 属性对应的字段名 */ public static <T> String getColumnName(Class<T> clazz, String propertyName) { String columnName = ""; PersistentClass persistentClass = getPersistentClass(clazz); Property property = persistentClass.getProperty(propertyName); Iterator<?> iterator = property.getColumnIterator(); if (iterator.hasNext()) { Column column = (Column) iterator.next(); columnName += column.getName(); } return columnName; } @Override public void setApplicationContext(ApplicationContext context) throws BeansException { applicationContext = context; } }
<span style="white-space:pre"> </span><bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="hibernateProperties"> <props> <prop key="hibernate.hbm2ddl.auto">update</prop> <prop key="hibernate.show_sql">true</prop> <prop key="hibernate.format_sql">true</prop> </props> </property> <property name="mappingResources"> <list> <value>bean/User.hbm.xml</value> </list> </property> </bean> <bean class="util.HibernateConfigurationUtil" />
package bean; public class User { private int id; private String username; private String password; public int getId() { return id; } public void setId(int id) { this.id = id; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } }User.hbm.xml
<?xml version='1.0' encoding='utf-8'?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd"> <hibernate-mapping> <class name="bean.User" table="_user"> <id name="id" type="int"> <column name="id" /> <generator class="increment" /> </id> <property name="username" type="string"> <column name="_username" /> </property> <property name="password" type="string"> <column name="_password" /> </property> </class> </hibernate-mapping>下面是测试代码
new ClassPathXmlApplicationContext("applicationContext.xml"); System.out.println(HibernateConfigurationUtil.getTableName(User.class)); System.out.println(HibernateConfigurationUtil.getPKColumnName(User.class)); System.out.println(HibernateConfigurationUtil.getColumnName(User.class,"username"));
Hibernate--根据实体类获得表名、主键名、字段名(与Spring集成)
原文地址:http://blog.csdn.net/zhangjk1993/article/details/40020813