码迷,mamicode.com
首页 > 编程语言 > 详细

python学习(24) 使用Xpath解析并抓取美女图片

时间:2018-11-18 22:38:26      阅读:325      评论:0      收藏:0      [点我收藏+]

标签:ade   python   源码   __init__   one   表达   for   asn   misc   

Xpath最初用来处理XML解析,同样适用于HTML文档处理。相比正则表达式更方便一些

Xpath基本规则

nodename   表示选取nodename 节点的所有子节点
/          表示当前节点的直接子节点
//         表示当前节点的子节点和孙子节点
.          表示当前节点
..         当前节点的父节点
@          选取属性

 

下面举例使用下

text = ‘‘‘
<div class="bus_vtem">
        <a href="https://www.aisinei.org/thread-17826-1-1.html" title="XINGYAN星颜社 2018.11.09 VOL.096 唐思琪 [47+1P]" class="preview"  target="_blank">
        <img src="https://i.asnpic.win/block/74/74eab64cfa4229d58c19a64970368178.jpg" width="250" height="375" alt="XINGYAN星颜社 2018.11.09 VOL.096 唐思琪 [47+1P]"/>
                <span class="bus_listag">XINGYAN星颜社</span>
        </a>
        <a href="https://www.aisinei.org/thread-17826-1-1.html" title="XINGYAN星颜社 2018.11.09 VOL.096 唐思琪 [47+1P]"  target="_blank">
            <div class="lv-face"><img src="https://www.aisinei.org/uc_server/avatar.php?uid=2&size=small" alt="发布组小乐"/></div>
            <div class="t">XINGYAN星颜社 2018.11.09 VOL.096 唐思琪 </div>
            <div class="i"><span><i class="bus_showicon bus_showicon_v"></i>5401</span><span><i class="bus_showicon bus_showicon_r"></i>1</span></div>
        </a>
    </div>
‘‘‘
from lxml import etree
html = etree.HTML(text)
result = etree.tostring(html)
#打印lxml生成的字符串,如果html格式不全,会自动补全
print(result.decode(utf-8))
# 打印根节点下所有子孙节点
result2 = html.xpath(//*)
print(result2)
result3 = html.xpath(//a[@class="preview"])
print(result3)

 

result.decode(‘utf-8’) 可以补全缺失的html格式字符串
html.xpath(‘//*’)查找根节点下所有子孙节点
html.xpath(‘//a[@class=”preview”]’) 在根节点所有子孙节点中找到属性class为preview的a节点。

lxml同样可以读取文件

from lxml import etree
html = etree.parse(./test.html,etree.HTMLParser())

 

lxml 操作子节点

from lxml import etree
html = etree.HTML(text)
result = html.xpath(//bus/a)

操作父节点

from lxml import etree
html = etree.HTML(text)
result = html.xpath(//a[@class="preview"]/../@class)
print(result)

先找到class属性为preview的a节点,然后找到其父节点,接着筛选父节点的class属性,打印结果为[‘bus_vtem’]

属性匹配

上面已经写过了格式为: 节点名[@属性名=”属性值”]

属性获取

上面已经谢过了,格式为: 节点名/@属性名,注意这里没有[]

多属性值匹配

上面的节点bus 属性class 只有一个值bus_vtem,如果新增一个值mtest,那么属性匹配要更换为contains,不然会报错

from lxml import etree
text2 = ‘‘‘
        <div class="bus_vtem  mtest"> hurricane!
        </div>
    ‘‘‘
html2 = etree.HTML(text2)    
result5 = html2.xpath(//*[contains(@class, "mtest")])
# 错误用法
#result5 = html.xpath(‘//*[@class="mtest"]‘)
print(result5)

 

多属性匹配

多属性匹配用于筛选一个节点时非常方便,各个属性的判断可以用 and or != == 等操作

from lxml import etree
text3 = ‘‘‘
        <div class="bus_vtem mtest" name="hurricane"> hurricane!
        </div>
        <div class="bus_vtem mtest" name = "tornado"> tornado!
        </div>
    ‘‘‘
html3 = etree.HTML(text3)    
result6 = html3.xpath(//*[contains(@class, "mtest") and @name="hurricane"]/text())
print(result6)

 

文本获取

在节点后加/text()即可,如
result6 = html3.xpath(‘//*[contains(@class, “mtest”) and @name=”hurricane”]/text()’)

下面结合前边讲述的request,cookie,以及今天的lxml知识,实战爬取艾丝新发布的美女图片地址,代码如下

import requests
import re
import time
from lxml import etree

USER_AGENT = Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/49.0.2623.221 Safari/537.36 SE 2.X MetaSr 1.0
COOKIES = r__cfduid=d78f862232687ba4aae00f617c0fd1ca81537854419; bg5D_2132_saltkey=jh7xllgK; bg5D_2132_lastvisit=1540536781; bg5D_2132_auth=479fTpQgthFjwwD6V1Xq8ky8wI2dzxJkPeJHEZyv3eqJqdTQOQWE74ttW1HchIUZpgsyN5Y9r1jtby9AwfRN1R89; bg5D_2132_lastcheckfeed=7469%7C1541145866; bg5D_2132_st_p=7469%7C1541642338%7Cda8e3f530a609251e7b04bfc94edecec; bg5D_2132_visitedfid=52; bg5D_2132_viewid=tid_14993; bg5D_2132_ulastactivity=caf0lAnOBNI8j%2FNwQJnPGXdw6EH%2Fj6DrvJqB%2Fvv6bVWR7kjOuehk; bg5D_2132_smile=1D1; bg5D_2132_seccode=22485.58c095bd095d57b101; bg5D_2132_lip=36.102.208.214%2C1541659184; bg5D_2132_sid=mElHBZ; Hm_lvt_b8d70b1e8d60fba1e9c8bd5d6b035f4c=1540540375,1540955353,1541145834,1541562930; Hm_lpvt_b8d70b1e8d60fba1e9c8bd5d6b035f4c=1541659189; bg5D_2132_sendmail=1; bg5D_2132_checkpm=1; bg5D_2132_lastact=1541659204%09misc.php%09patch
class AsScrapy(object):
    def __init__(self,pages=1):
        try:
            self.m_session = requests.Session()
            self.m_headers = {User-Agent:USER_AGENT,
                        #‘referer‘:‘https://www.aisinei.org/‘,
                        }
           
            self.m_cookiejar = requests.cookies.RequestsCookieJar()
            for cookie in COOKIES.split(;):
                key,value = cookie.split(=,1)
                self.m_cookiejar.set(key,value)
        except:
            print(init error!!!)
    def getOverView(self):
        try:
            req = self.m_session.get(https://www.aisinei.org/portal.php,headers=self.m_headers, cookies=self.m_cookiejar, timeout=5)
            html = etree.HTML(req.content.decode(utf-8))
            #result=html.xpath(‘//div[@class="bus_vtem"]/a[@title!="紧急通知!紧急通知!紧急通知!"]/attribute::*‘)
            #print(result)
            htmllist = html.xpath(//div[@class="bus_vtem"]/a[@title!="紧急通知!紧急通知!紧急通知!" and @class="preview"]/@href)
            titlelist = html.xpath(//div[@class="bus_vtem"]/a[@title!="紧急通知!紧急通知!紧急通知!" and @class="preview"]/@title)
            print(htmllist)
            print(titlelist)
            print(len(htmllist))
            print(len(titlelist))            
            time.sleep(1)
            pass
        except:
            print(get over view error)

if __name__ == "__main__":
    asscrapy = AsScrapy()
    asscrapy.getOverView()

 

通过lxml分析,可以摘取资源地址
技术分享图片
接下来爬取图片,读者可以发送request请求即可,留作课后题吧。
源码下载地址
https://github.com/secondtonone1/python-
谢谢关注我的公众号
技术分享图片

python学习(24) 使用Xpath解析并抓取美女图片

标签:ade   python   源码   __init__   one   表达   for   asn   misc   

原文地址:https://www.cnblogs.com/secondtonone1/p/9979596.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!