标签：else 列表 学编程 解法 应该 nbsp 思考 com sum
1 # 传统的杨辉三角形实现
2 def pascal(row):
3 result_list = [0] * (row * 2 + 1)
4
5 for row_loc in range(row):
6 base_loc = row - row_loc - 1
7 if row_loc == 0:
8 result_list[base_loc] = 1
9 else:
10 result_list[base_loc] = result_list[base_loc + 1]
11 for line_loc in range(row_loc):
12 now_loc = base_loc + (line_loc + 1) * 2
13 result_list[now_loc] = result_list[now_loc - 1] + result_list[now_loc + 1]
14 result_list[now_loc - 1] = 0
15
16 print str(result_list) 17 .replace("]", ",").replace(" 0,", " ").replace(",", "").replace("[0", " ").replace("[", " ")
18
19 pascal(15)
1 # 利用python列表迭代的实现
2 def printLine(lineList,row):
3 lineList = [str(tmpNum) for tmpNum in lineList]
4 print("%s%s" % (" " * (row - len(lineList)), " ".join(lineList)))
5
6 def pascal(row):
7 for i in range(row):
8 if i < 2:
9 yhList = [1] * (i + 1)
10 else:
11 yhList[1:-1] = [(tmpNum + yhList[j]) for j, tmpNum in enumerate(yhList[1:])]
12 printLine(yhList,row)
13
14 pascal(10)
1 # 基于函数式编程思路的实现 2 def row(x): 3 return ‘ ‘.join(map(str, reduce(lambda x, y: map( sum, zip([0] + x, x + [0]) ), range(x), [1] ))) 4 5 def pascal(x): 6 return ‘\n‘.join(row(i).center(len(row(x - 1))) for i in range(x)) 7 8 print pascal(10)
标签：else 列表 学编程 解法 应该 nbsp 思考 com sum
原文地址：https://www.cnblogs.com/kevins-yuan/p/9990449.html
