改写python round()函数，解决四舍五入问题 round(1.365,2)=1.36

print(round(1.365,2)) #1.36 没进一
print(‘%.2f‘%1.365)
print(round(1.3651,2)) #1.37 对的
print(‘%.2f‘%1.3651)
print(round(1.465,2)) #1.47 对的
print(‘%.2f‘%1.465)

def round_rewrite(data,i=0):
    ‘‘‘
    四舍五入,解决round(7.35)=7.3的问题
    :param data:
    :param i: 保留的位数,默认0
    :return:
    ‘‘‘
    if type(i) != type(1): #i是整数
        raise TypeError(‘the second param must be int‘)
    else:
        mi = 10**i
        datax = data*mi
        f = datax - int(datax)
        if f >=0.5:
            res = (int(datax)+1)/mi
        elif f <=-0.5:
            res = (int(datax)-1)/mi
        else:
            res = int(datax)/mi

        if i <= 0:
            res = int(res)
    return res

data = 1.365
print(round(data,2))
print(round_rewrite(data,2))