标签:sts present mit [] max out atm 没有 style
1 public class StreamUtils { 2 3 4 5 private static final List<Integer> listInteger = Lists.newArrayList(1, 2, 3, 4, 5, 6, 3, 5, 1, 4, 2, 8, 9); 6 7 private static final List<Integer> arrayList = Lists.newArrayList(1, 25, 6, 9, 22, 44); 8 9 public static void main(String[] args) { 10 ///取%2的数 11 List<Integer> collect = listInteger.stream().filter(i -> i % 2 == 0).collect(Collectors.toList()); 12 System.out.println(collect); 13 ///去重 14 List<Integer> collect1 = listInteger.stream().distinct().collect(Collectors.toList()); 15 System.out.println(collect1); 16 17 ///跳过前面3个元素 18 List<Integer> collect2 = listInteger.stream().skip(3).collect(Collectors.toList()); 19 System.out.println(collect2); 20 21 ///取前面3个元素 22 List<Integer> collect3 = listInteger.stream().limit(3).collect(Collectors.toList()); 23 System.out.println(collect3); 24 25 ///打印dish getName集合 26 List<String> collect4 = list.stream().map(Dish::getName).collect(Collectors.toList()); 27 System.out.println(collect4); 28 29 String[] helloWord = {"hellow", "word"}; 30 ///{h,e,l,l,o,w},{w,o,r,d} 31 Stream<String[]> stream = Arrays.stream(helloWord).map(s -> s.split("")); 32 ///h,e,l,l,o,w,w,o,r,d || flatMap 扁平化操作接受stream 33 Stream<String> stringStream = stream.flatMap(Arrays::stream); 34 ///去重 35 stringStream.distinct().forEach(System.out::println); 36 //allMatch 所有的元素的满足条件 37 System.out.println(arrayList.stream().allMatch(i -> i > 50)); 38 39 ///anyMatch 当元素数组中有一个元素满足就返回true 40 System.out.println(arrayList.stream().anyMatch(i -> i > 40)); 41 42 ///noneMatch 没有一个元素满足的情况下返回true 43 System.out.println(arrayList.stream().noneMatch(i -> i < 0)); 44 45 ///findAny随机获取一个元素 46 Optional<Integer> any = arrayList.stream().filter(i -> i > 2).findAny(); 47 System.out.println(any.get()); 48 49 ///Options 中的orElse 如果返回结果是null使用orElse可以设置默认值,返回-1 50 Integer integer = arrayList.stream().filter(i -> i > 66).findAny().orElse(-1); 51 System.out.println(integer); 52 53 ///isPresent元素是否存在,ifPresent 元素存在需要做什么事情 54 Optional<Integer> first = arrayList.stream().filter(i -> i > 10).findFirst(); 55 System.out.println("optional元素是否存在:"+first.isPresent()); 56 first.ifPresent(System.out::println); 57 58 //reduce 聚合函数 将数组中的元素累加 0设置默认值初始值 59 Integer sum = arrayList.stream().reduce(0, (x, y) -> x + y); 60 System.out.println(sum); 61 62 ///打印数组中累加的值 63 arrayList.stream().reduce((x,y)->x+y).ifPresent(System.out::println); 64 65 ///获取数组中的最大值 66 System.out.println(arrayList.stream().reduce(Integer::max).get()); 67 ///获取数组最小值 68 System.out.println(arrayList.stream().reduce(Integer::min).get()); 69 70 ///累加 71 arrayList.stream().reduce(Integer::sum).ifPresent(System.out::println); 72 73 74 } 75 }
标签:sts present mit [] max out atm 没有 style
原文地址:https://www.cnblogs.com/houqijun/p/10090989.html