*** 82 删除排序链表中的重复元素II

标签：nod   删除   ***   ret   ted   class   else   cat   next   

    ListNode *deleteDuplicates(ListNode *head) {
        if (head == nullptr || head->next == nullptr)
            return head;
        ListNode prehead(-1);
        prehead.next = head;
        head = &prehead;
        ListNode *left, *right;
        while (head->next) {
            left = head->next;
            right = left;
            while (right->next && right->next->val == left->val)
                right = right->next;
            if (left == right)
                head = head->next;
            else
                head->next = right->next;
        }
        return prehead.next;
    }

*** 82 删除排序链表中的重复元素II

标签：nod   删除   ***   ret   ted   class   else   cat   next   

原文地址：https://www.cnblogs.com/INnoVationv2/p/10176351.html