码迷,mamicode.com
首页 > 数据库 > 详细

实战演示疑惑 mysql insert到底加什么锁

时间:2018-12-26 11:34:41      阅读:245      评论:0      收藏:0      [点我收藏+]

标签:简单   实验   def   cti   中文   form   解析   exec   values   

innodb的事务隔离级别是可重复读级别且innodb_locks_unsafe_for_binlog禁用,也就是说允许next-key lock

 实验来自网上. ( 如果你没有演示出来,请check order_id 是否是非unique key.) 如果你看不懂,请看后续文章. next-key lock (glap lock)完全解析.

CREATE TABLE `LockTest` (

   `order_id` varchar(20) NOT NULL,
   `id` bigint(20) NOT NULL AUTO_INCREMENT,
   PRIMARY KEY (`id`),
   KEY `idx_order_id` (`order_id`)
 ) ENGINE=InnoDB AUTO_INCREMENT=16 DEFAULT CHARSET=utf8

 select * from LockTest;

 empty set;

事务1 事务2
begin

delete from LockTest where order_id =  ‘D20‘

 
 
 

begin
delete from LockTest where order_id =  ‘D19‘

insert into LockTest (order_id) values (‘D20‘)

 
 
insert into LockTest (order_id) values (‘D19‘)

commit
commit

 

事务1 执行到insert语句会block住,事务2执行insert语句会提示死锁错误

 

错误码: 1213
Deadlock found when trying to get lock; try restarting transaction

Execution Time : 00:00:00:000
Transfer Time : 00:00:00:000
Total Time : 00:00:00:000

 

 show engine innodb status 显示死锁信息

------------------------
LATEST DETECTED DEADLOCK
------------------------
2014-04-30 15:01:55 a233b90
*** (1) TRANSACTION:
TRANSACTION 596042, ACTIVE 7 sec inserting
mysql tables in use 1, locked 1
LOCK WAIT 3 lock struct(s), heap size 320, 2 row lock(s), undo log entries 1
MySQL thread id 10851, OS thread handle 0x2abfb90, query id 251521 10.10.53.122 root update
insert into LockTest (order_id) values (‘D20‘)
*** (1) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 502 page no 4 n bits 72 index `idx_order_id` of table `test`.`LockTest` trx id 596042 lock_mode X insert intention waiting
Record lock, heap no 1 PHYSICAL RECORD: n_fields 1; compact format; info bits 0
0: len 8; hex 73757072656d756d; asc supremum;;

*** (2) TRANSACTION:
TRANSACTION 596041, ACTIVE 19 sec inserting
mysql tables in use 1, locked 1
3 lock struct(s), heap size 320, 2 row lock(s), undo log entries 1
MySQL thread id 10848, OS thread handle 0xa233b90, query id 251522 10.10.53.122 root update
insert into LockTest (order_id) values (‘D19‘)
*** (2) HOLDS THE LOCK(S):
RECORD LOCKS space id 502 page no 4 n bits 72 index `idx_order_id` of table `test`.`LockTest` trx id 596041 lock_mode X
Record lock, heap no 1 PHYSICAL RECORD: n_fields 1; compact format; info bits 0
0: len 8; hex 73757072656d756d; asc supremum;;

*** (2) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 502 page no 4 n bits 72 index `idx_order_id` of table `test`.`LockTest` trx id 596041 lock_mode X insert intention waiting
Record lock, heap no 1 PHYSICAL RECORD: n_fields 1; compact format; info bits 0
0: len 8; hex 73757072656d756d; asc supremum;;

*** WE ROLL BACK TRANSACTION (2)

简单分析上面的场景先删除再插入的sql是hibernage保存集合关联的处理方式。delete语句删除不存在且删除的order_id大于现有表中的所有order_id,所以delete语句会使用next-key锁住(当前最大-无穷大) 

lock_id lock_trx_id lock_mode lock_type lock_table lock_index lock_space lock_page lock_rec lock_data
596133:502:4:1 596133 X RECORD `test`.`LockTest` idx_order_id 502 4 1 supremum pseudo-record
596134:502:4:1 596134 X RECORD `test`.`LockTest` idx_order_id 502 4 1 supremum pseudo-record
 

比较奇怪的是为啥两个事务都拿到了相同区间的(当前最大-无穷大)的X锁。不过换成read-commited级别后就没死锁了。

终于在官方文档找到答案, 区间锁只是用来防止其他事务在区间中插入数据,区间x锁 与区间S锁效果是一样的。也就是说不会因为两个事务都用加相同区间锁而相互等待的

https://dev.mysql.com/doc/refman/5.1/en/innodb-record-level-locks.html

Gap locks in InnoDB are “purely inhibitive”, which means they only stop other transactions from inserting to the gap. Thus, a gap X-lock has the same effect as a gap S-lock.

 

当两个事务拿到相同区间锁后,就会阻止对方忘区间内做insert操作。所以第一个事务insert会阻塞,第二个事务会提示死锁

详情见 https://dev.mysql.com/doc/refman/5.6/en/innodb-record-level-locks.html

换成read-commited级别后就没死锁了! 因为没有了间隙所,读提交不需要幻读控制,也就不需要间隙锁了.

万变归一: 事务内加锁总归是为了隔离级别.

 

再来分析另外一个现象:

    上述现象表明, delete/update会阻塞insert .那么换成先insert,再delete/update呢?

    实验表明不会阻塞?  这个感觉挺矛盾的,锁的互斥是相对的. 主要原因是insert 不会产生 间隙锁.

间隙锁的作用本身就是单向的.

 

再次从事务内加锁原因是为了隔离级别这个角度分析.  insert 

 

【解决方案有两种】
1、改变程序中数据库操作的逻辑
2、取消gap lock机制 
innodb_locks_unsafe_for_binlog启用

或者设置为隔离级别为读提交
Gap locking can be disabled explicitly.This occurs if you change the transaction isolation level to READ COMMITTED orenable the innodb_locks_unsafe_for_binlog system variable.
3. 加上unique锁


select for update / update  where 

1. 有该行  对非unique列会加 间隙共享锁 和 行锁 见 (14.2.2.4 InnoDB Record, Gap, and Next-Key Locks http://dev.mysql.com/doc/refman/5.7/en/innodb-record-level-locks.html)

2. 无该行 对非unique  会加间隙共享锁  . 这个文档比较麻烦. 要通过 上面(该文)

   (Unexpected deadlock between concurrent INSERTs when unique key violation may occ http://bugs.mysql.com/bug.php?id=35821)和

   (Deadlock detected on concurrent insert into same table (InnoDB) https://bugs.mysql.com/bug.php?id=43210 )

里面有个很好玩的案例,这两个中文博客里也是该话题 (innodb next-key lock引发的死锁 http://www.cnblogs.com/xhan/p/3701459.html)
---------------------
原文:https://blog.csdn.net/fei33423/article/details/46731891

实战演示疑惑 mysql insert到底加什么锁

标签:简单   实验   def   cti   中文   form   解析   exec   values   

原文地址:https://www.cnblogs.com/DataArt/p/10177905.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!