标签：方法 === div res class OLE ons result color
1.求交集
var arr1 = [{name:‘name1‘,id:1},{name:‘name2‘,id:2},{name:‘name3‘,id:3}];
var arr1Id = [1,2,3]
var arr2 = [{name:‘name1‘,id:1},{name:‘name2‘,id:2},{name:‘name3‘,id:3},{name:‘name4‘,id:4},{name:‘name5‘,id:5}];
var result = arr2.filter(function(v){
return arr1Id.indexOf(v.id)!==-1 // 利用filter方法来遍历是否有相同的元素
})
console.log(result);
2.求并集
let arr1 = [{name:‘name1‘,id:1},{name:‘name2‘,id:2},{name:‘name3‘,id:3}];
let arr2 = [{name:‘name1‘,id:1},{name:‘name4‘,id:4},{name:‘name5‘,id:5}];
let arr3 = arr1.concat(arr2);
let result = [];
var obj = [];
result = arr3.reduce(function(prev, cur, index, arr) {
console.log(prev, cur);
obj[cur.id] ? ‘‘ : obj[cur.id] = true && prev.push(cur);
return prev;
}, []);
console.log(result);
3.求差集
let arr1 = [{name:‘name1‘,id:1},{name:‘name2‘,id:2},{name:‘name3‘,id:3}]; let arr1Id = [1,2,3]; let arr2 = [{name:‘name1‘,id:1},{name:‘name4‘,id:4},{name:‘name5‘,id:5}]; let arr2Id = [1,4,5]; let arr3 = arr1.concat(arr2); let result = arr3.filter(function(v){ return arr1Id.indexOf(v.id)===-1 || (arr2Id.indexOf(v.id)===-1) }) console.log(result);
4.去重
let arr = [{name:‘name1‘,id:1},{name:‘name2‘,id:2},{name:‘name3‘,id:3},{name:‘name1‘,id:1},{name:‘name4‘,id:4},{name:‘name5‘,id:5}];
var obj = [];
let result = arr.reduce(function(prev, cur, index, arr) {
console.log(prev, cur);
obj[cur.id] ? ‘‘ : obj[cur.id] = true && prev.push(cur);
return prev;
}, []);
标签：方法 === div res class OLE ons result color
原文地址：https://www.cnblogs.com/cx709452428/p/10180807.html
