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[LeetCode&Python] Problem 235. Lowest Common Ancestor of a Binary Search Tree

时间:2018-12-26 20:24:22      阅读:132      评论:0      收藏:0      [点我收藏+]

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Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.

According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q as descendants (where we allow a node to be a descendant of itself).”

Given binary search tree:  root = [6,2,8,0,4,7,9,null,null,3,5]

技术分享图片

 

Example 1:

Input: root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 8
Output: 6
Explanation: The LCA of nodes 2 and 8 is 6.

Example 2:

Input: root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 4
Output: 2
Explanation: The LCA of nodes 2 and 4 is 2, since a node can be a descendant of itself according to the LCA definition.

 

Note:

  • All of the nodes‘ values will be unique.
  • p and q are different and both values will exist in the BST.
# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution(object):
    def lowestCommonAncestor(self, root, p, q):
        """
        :type root: TreeNode
        :type p: TreeNode
        :type q: TreeNode
        :rtype: TreeNode
        """
        p_val=p.val
        q_val=q.val
        
        if p_val<root.val and q_val<root.val:
            return self.lowestCommonAncestor(root.left,p,q)
        elif p_val>root.val and q_val>root.val:
            return self.lowestCommonAncestor(root.right,p,q)
        else:
            return root

  

[LeetCode&Python] Problem 235. Lowest Common Ancestor of a Binary Search Tree

标签:分享图片   put   targe   sea   highlight   The   etc   treenode   object   

原文地址:https://www.cnblogs.com/chiyeung/p/10180831.html

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