标签：create HERE enc this app article inter targe dea
According to the Wikipedia‘s article: "The Game of Life, also known simply as Life, is a cellular automaton devised by the British mathematician John Horton Conway in 1970."
Given a board with m by n cells, each cell has an initial state live (1) or dead (0). Each cell interacts with its eight neighbors (horizontal, vertical, diagonal) using the following four rules (taken from the above Wikipedia article):
Write a function to compute the next state (after one update) of the board given its current state. The next state is created by applying the above rules simultaneously to every cell in the current state, where births and deaths occur simultaneously.
Example:
Input:
[
[0,1,0],
[0,0,1],
[1,1,1],
[0,0,0]
]
Output:
[
[0,0,0],
[1,0,1],
[0,1,1],
[0,1,0]
]
Follow up:
矩阵中每个元素为1（live）或0（dead），题目给出了细胞更新的规则，求出更新后的矩阵。规则如下：
首先先判断元素是0还是1，再计算周围八个元素的值的和，根据规则更新。创建一个新的二维数组，最后将计算的值赋给原数组。
class Solution { public: void gameOfLife(vector<vector<int>>& board) { vector<vector<int>> res; vector<int> temp; for (int i = 0; i < board.size(); i++){ for (int j = 0; j < board[0].size(); j++){ //dead cell if (board[i][j] == 0){ int alive = 0; for (int m = i-1; m <= i+1; m++){ for (int n = j-1; n <= j+1; n++){ if (m < 0 || m >= board.size() || n < 0 || n >= board[0].size()) continue; else{ if (board[m][n] == 1) alive++; } } } if (alive == 3) temp.push_back(1); else temp.push_back(0); } //live cell else{ int al = 0; for (int m = i-1; m <= i+1; m++){ for (int n = j-1; n <= j+1; n++){ if (m < 0 || m >= board.size() || n < 0 || n >= board[0].size()) continue; else{ if (board[m][n] == 1) al++; } } } //计算了board[m][n]的值，所以判断条件+1 if (al < 3) temp.push_back(0); else if (al > 4) temp.push_back(0); else temp.push_back(1); } } res.push_back(temp); temp.clear(); } for (int i = 0; i < board.size(); i++){ for (int j = 0; j < board[0].size(); j++){ board[i][j] = res[i][j]; } } } };
做法是新开辟了一个数组，以后再更新下用原数组的程序。
LeetCode 289. Game of Life (C++)
标签：create HERE enc this app article inter targe dea
原文地址：https://www.cnblogs.com/silentteller/p/10192457.html
