标签:can fir this using methods 相等 with sed ever
let arrayEquals = (array1, array2) => { // if array1 or array2 is a falsy value, return if (!array1 || !array2) return false; // compare lengths - can save a lot of time if (array1.length != array2.length) return false; for (var i = 0, l = array1.length; i < l; i++) { // Check if we have nested arrays if (array1[i] instanceof Array && array2[i] instanceof Array) { // recurse into the nested arrays if (!arrayEquals(array1[i],array2[i] )) return false; } else if (array1[i] instanceof Object && array2[i] instanceof Object){ // 比较含有的对象是否相等 if (!objectEquals(array1[i],array2[i])) return false; } else if (array1[i] != array[i]) { console.log("else if") // Warning - two different object instances will never be equal: {x:20} != {x:20} return false; } } return true; } let objectEquals = (object1, object2) => { //For the first loop, we only check for types for (let propName in object1) { //Check for inherited methods and properties - like .equals itself //https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/hasOwnProperty //Return false if the return value is different if (object1.hasOwnProperty(propName) != object2.hasOwnProperty(propName)) { return false; } //Check instance type else if (typeof object1[propName] != typeof object2[propName]) { //Different types => not equal return false; } } //Now a deeper check using other objects property names for(let propName in object2) { //We must check instances anyway, there may be a property that only exists in object2 //I wonder, if remembering the checked values from the first loop would be faster or not if (object1.hasOwnProperty(propName) != object2.hasOwnProperty(propName)) { return false; } else if (typeof object1[propName] != typeof object2[propName]) { return false; } //If the property is inherited, do not check any more (it must be equa if both objects inherit it) if(!object1.hasOwnProperty(propName)) continue; //Now the detail check and recursion //This returns the script back to the array comparing /**REQUIRES Array.equals**/ if (object1[propName] instanceof Array && object2[propName] instanceof Array) { // recurse into the nested arrays if (!arrayEquals(object1[propName], object2[propName])) return false; } else if (object1[propName] instanceof Object && object2[propName] instanceof Object) { // recurse into another objects //console.log("Recursing to compare ", object1[propName],"with",object2[propName], " both named \""+propName+"\""); if (!objectEquals(object1[propName],object2[propName])) return false; } //Normal value comparison for strings and numbers else if(object1[propName] != object2[propName]) { return false; } } //If everything passed, let‘s say YES return true; } let equals = { arrayEquals, objectEquals } window.equals = equals; module.exports = equals;
标签:can fir this using methods 相等 with sed ever
原文地址:https://www.cnblogs.com/gwf93/p/10209639.html