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【c++】生成浮点随机数

时间:2019-01-26 17:56:57      阅读:156      评论:0      收藏:0      [点我收藏+]

标签:col   sign   10个   for   generated   1.5   dom   之间   ble   

 

c++11:std::uniform_real_distribution<>直接求(尖括号不填默认生成double)

随机10个在1-2之间的浮点数

#include <random>
#include <iostream>
 
int main()
{
    std::random_device rd;  //Will be used to obtain a seed for the random number engine
    std::mt19937 gen(rd()); //Standard mersenne_twister_engine seeded with rd()
    std::uniform_real_distribution<> dis(1.0, 2.0);
    for (int n = 0; n < 10; ++n) {
        // Use dis to transform the random unsigned int generated by gen into a 
        // double in [1, 2). Each call to dis(gen) generates a new random double
        std::cout << dis(gen) <<  ;
    }
    std::cout << \n;
}

结果:

1.80829 1.15391 1.18483 1.38969 1.36094 1.0648 1.97798 1.27984 1.68261 1.57326

https://en.cppreference.com/w/cpp/numeric/random/uniform_real_distribution

 

 

c++11 之前:通过std::rand()和RAND_MAX间接求

如果要实现0-1之间随机浮点数的函数,可以如下: 

double randf() { 
     return (double)(rand()/(double)RAND_MAX); 
} 

https://blog.csdn.net/enterlly/article/details/54310945

 

【c++】生成浮点随机数

标签:col   sign   10个   for   generated   1.5   dom   之间   ble   

原文地址:https://www.cnblogs.com/zealousness/p/10324170.html

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