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C++反编译-类与结构体分析三

时间:2019-01-27 13:03:52      阅读:218      评论:0      收藏:0      [点我收藏+]

标签:turn   color   函数   ons   main   add   \n   sub   strcpy   

main函数
;15 :    {
0x40137a    push   %ebp
0x40137b    mov    %esp,%ebp
0x40137d    and    $0xfffffff0,%esp
0x401380    sub    $0x60,%esp
0x401383    call   0x427130 <__main>
;16 :        A a;
;17 :        a.a = 1;
0x401388    movl   $0x1,0x38(%esp)
;18 :        a.b = 2;
0x401390    movl   $0x2,0x3c(%esp)
;19 :        strcpy(a.c, "this is question");
0x401398    lea    0x38(%esp),%eax
0x40139c    add    $0x8,%eax
0x40139f    movl   $0x73696874,(%eax)
0x4013a5    movl   $0x20736920,0x4(%eax)
0x4013ac    movl   $0x73657571,0x8(%eax)
0x4013b3    movl   $0x6e6f6974,0xc(%eax)
0x4013ba    movb   $0x0,0x10(%eax)
;20 :        printAll(a);
0x4013be    mov    0x38(%esp),%eax //下面0x8字节为参数a和参数b
0x4013c2    mov    %eax,(%esp)
0x4013c5    mov    0x3c(%esp),%eax
0x4013c9    mov    %eax,0x4(%esp)
0x4013cd    mov    0x40(%esp),%eax //下面0x20字节为字符数组c有的+没的
0x4013d1    mov    %eax,0x8(%esp)
0x4013d5    mov    0x44(%esp),%eax
0x4013d9    mov    %eax,0xc(%esp)
0x4013dd    mov    0x48(%esp),%eax
0x4013e1    mov    %eax,0x10(%esp)
0x4013e5    mov    0x4c(%esp),%eax
0x4013e9    mov    %eax,0x14(%esp)
0x4013ed    mov    0x50(%esp),%eax
0x4013f1    mov    %eax,0x18(%esp)
0x4013f5    mov    0x54(%esp),%eax
0x4013f9    mov    %eax,0x1c(%esp)
0x4013fd    mov    0x58(%esp),%eax
0x401401    mov    %eax,0x20(%esp)
0x401405    mov    0x5c(%esp),%eax
0x401409    mov    %eax,0x24(%esp)
0x40140d    call   0x401350 <printAll(A)>
;21 :        return 0;
0x401412    mov    $0x0,%eax
;22 :    }
0x401417    leave
0x401418    ret
printAll函数
;11 :    void printAll(A a) {
0x401350    push   %ebp
0x401351    mov    %esp,%ebp
0x401353    sub    $0x18,%esp //变量总数据长度为0x18字节
;12 :        printf("%d,%d %s\n", a.a, a.b, a.c);
0x401356    mov    0xc(%ebp),%edx //此处edx = 2
0x401359    mov    0x8(%ebp),%eax //此处eax = 1
0x40135c    lea    0x10(%ebp),%ecx //此处ecx为字符数组首地址
0x40135f    mov    %ecx,0xc(%esp)
0x401363    mov    %edx,0x8(%esp)
0x401367    mov    %eax,0x4(%esp)
0x40136b    movl   $0x4b9025,(%esp)
0x401372    call   0x4b5890 <printf(char const*, ...)>
;13 :    }
0x401377    nop
0x401378    leave
0x401379    ret

 

C++反编译-类与结构体分析三

标签:turn   color   函数   ons   main   add   \n   sub   strcpy   

原文地址:https://www.cnblogs.com/reverse201/p/10325886.html

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