C语言的函数声明，定义，调用以及exit退出

 1 #include <stdio.h>
 2 #include <stdlib.h>
 3 void singing();
 4 int main()
 5 {
 6     singing();
 7     system("pause");
 8 }
 9 
10 void singing()
11 {
12     printf("after party~after party~我已然赶不上地铁\n");
13 }

#include <stdio.h>
#include <stdlib.h>
void singing(char[]);
int main()
{
    singing("新裤子");
    system("pause");
}

void singing(char  clipname[])
{
    
    printf("专辑名称:%s========after party~after party~我已然赶不上地铁\n",clipname);
}

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#pragma warning(disable:4996)
char * singing(char[]);
int main()
{
    char prtline[200] = {0};
    strcat(prtline,singing("新裤子"));
    printf("%s", prtline);
    system("pause");
}

char * singing(char  clipname[])
{
    
    /*printf("专辑名称:%s========after party~after party~我已然赶不上地铁\n",clipname);*/
    char finalstr[200] = {0};
    strcat(finalstr, "专辑名称:");
    strcat(finalstr, clipname);
    strcat(finalstr, "========after party~after party~我已然赶不上地铁\n");
    /*printf("%s", finalstr);*/
    return finalstr;
}
但凡遇到 char * 函数名 或者是 int * 函数名意味着，函数返回字符数组或者是整型数组
代码行#pragma warning(disable:4996)是考虑到strcat() strcpy()函数可能被弃用的事实
exit（）函数-----哪怕是在自定义函数中用一下，也会导致整个main函数的退出

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#pragma warning(disable:4996)
char * singing(char[]);
int main()
{
    char prtline[200] = {0};
    strcat(prtline,singing("新裤子"));
    printf("%s", prtline);
    system("pause");
}

char * singing(char  clipname[])
{
    
    /*printf("专辑名称:%s========after party~after party~我已然赶不上地铁\n",clipname);*/
    char finalstr[200] = {0};
    exit("操~爷不干了");
    strcat(finalstr, "专辑名称:");
    strcat(finalstr, clipname);
    strcat(finalstr, "========after party~after party~我已然赶不上地铁\n");
    /*printf("%s", finalstr);*/
    return finalstr;
}