说明：
通过MySQL的 information_schema 数据库，可查询数据库中每个表占用的空间、表记录的行数；该库中有一个 TABLES 表，这个表主要字段分别是：
TABLE_SCHEMA : 数据库名
TABLE_NAME：表名
ENGINE：所使用的存储引擎
TABLES_ROWS：记录数
DATA_LENGTH：数据大小
INDEX_LENGTH：索引大小
其他字段请参考MySQL的手册，查看一个表占用空间的大小，那就相当于是 数据大小 + 索引大小 。
查看所有库的大小
mysql> use information_schema; Database changed mysql> select concat(round(sum(DATA_LENGTH/1024/1024),2),‘MB‘) as data from TABLES; +----------+ | data | +----------+ | 104.21MB | +----------+ 1 row in set (0.11 sec)
查看指定库的大小
mysql> select concat(round(sum(DATA_LENGTH/1024/1024),2),‘MB‘) as data from TABLES where table_schema=‘jishi‘; +---------+ | data | +---------+ | 26.17MB | +---------+ 1 row in set (0.01 sec)
查看指定库的指定表的大小
mysql> select concat(round(sum(DATA_LENGTH/1024/1024),2),‘MB‘) as data from TABLES where table_schema=‘jishi‘ and table_name=‘a_ya‘; +--------+ | data | +--------+ | 0.02MB | +--------+ 1 row in set (0.00 sec)
查看指定库的索引大小
mysql> SELECT CONCAT(ROUND(SUM(index_length)/(1024*1024), 2), ‘ MB‘) AS ‘Total Index Size‘ FROM TABLES WHERE table_schema = ‘jishi‘; +------------------+ | Total Index Size | +------------------+ | 0.94 MB | +------------------+ 1 row in set (0.01 sec)
查看指定库的指定表的索引大小
mysql> SELECT CONCAT(ROUND(SUM(index_length)/(1024*1024), 2), ‘ MB‘) AS ‘Total Index Size‘ FROM TABLES WHERE table_schema = ‘test‘ and table_name=‘a_yuser‘;
+------------------+
| Total Index Size |
+------------------+
| 21.84 MB |
+------------------+
1 row in set (0.00 sec)
mysql> show create table test.a_yuser\G;
*************************** 1. row ***************************
Table: a_yuser
Create Table: CREATE TABLE `a_yuser` (
`email` varchar(60) NOT NULL DEFAULT ‘‘,
`user_name` varchar(60) NOT NULL DEFAULT ‘‘,
KEY `cc` (`email`(5)),
KEY `ccb` (`user_name`(5)),
KEY `ccbc` (`email`(5),`user_name`(5))
) ENGINE=MyISAM DEFAULT CHARSET=utf8
1 row in set (0.00 sec)
ERROR:
No query specified
mysql> select count(*) from test.a_yuser;
+----------+
| count(*) |
+----------+
| 1073607 |
+----------+
1 row in set (0.00 sec)
查看一个库中的情况
mysql> SELECT CONCAT(table_schema,‘.‘,table_name) AS ‘Table Name‘, CONCAT(ROUND(table_rows/1000000,4),‘M‘) AS ‘Number of Rows‘, CONCAT(ROUND(data_length/(1024*1024*1024),4),‘G‘) AS ‘Data Size‘, CONCAT(ROUND(index_length/(1024*1024*1024),4),‘G‘) AS ‘Index Size‘, CONCAT(ROUND((data_length+index_length)/(1024*1024*1024),4),‘G‘) AS‘Total‘FROM information_schema.TABLES WHERE table_schema LIKE ‘test‘; +---------------+----------------+-----------+------------+---------+ | Table Name | Number of Rows | Data Size | Index Size | Total | +---------------+----------------+-----------+------------+---------+ | test.a_br | 0.4625M | 0.0259G | 0.0171G | 0.0431G | | test.a_skuclr | 0.7099M | 0.0660G | 0.0259G | 0.0919G | | test.a_yuser | 1.0736M | 0.0497G | 0.0213G | 0.0710G | | test.test | 0.0000M | 0.0000G | 0.0000G | 0.0000G | +---------------+----------------+-----------+------------+---------+ 4 rows in set (0.13 sec)
参考网址：
http://www.oschina.net/question/12_3673
http://blog.sina.com.cn/s/blog_4c197d420101fbl9.html
标签：记录 base 有一个 数据库 图片 use str sch clr
原文地址：https://www.cnblogs.com/EikiXu/p/10407592.html
