标签:letter sequence single cti inpu ike seq cas color
44. Wildcard Matching
Given an input string (s
) and a pattern (p
), implement wildcard pattern matching with support for ‘?‘
and ‘*‘
.
‘?‘ Matches any single character. ‘*‘ Matches any sequence of characters (including the empty sequence).
The matching should cover the entire input string (not partial).
Note:
s
could be empty and contains only lowercase letters a-z
.p
could be empty and contains only lowercase letters a-z
, and characters like ?
or *
.Example 1:
Input: s = "aa" p = "a" Output: false Explanation: "a" does not match the entire string "aa".
Example 2:
Input: s = "aa" p = "*" Output: true Explanation: ‘*‘ matches any sequence.
Example 3:
Input: s = "cb" p = "?a" Output: false Explanation: ‘?‘ matches ‘c‘, but the second letter is ‘a‘, which does not match ‘b‘.
Example 4:
Input: s = "adceb" p = "*a*b" Output: true Explanation: The first ‘*‘ matches the empty sequence, while the second ‘*‘ matches the substring "dce".
Example 5:
Input: s = "acdcb" p = "a*c?b" Output: false
题意:实现通配符的匹配是否合法
代码如下:
/** * @param {string} s * @param {string} p * @return {boolean} */ var isMatch = function(s, p) { var m=s.length,n=p.length; var dp=[]; for(var i=0;i<=m;i++){ dp[i]=[]; for(var j=0;j<=n;j++){ dp[i][j]=false; } } dp[0][0]=true; for(var i=1;i<=n;i++){ if(p[i-1]===‘*‘) dp[0][i]=dp[0][i-1]; } for(var i=1;i<=m;i++){ for(var j=1;j<=n;j++){ if(p[j-1]===‘*‘){ dp[i][j]=dp[i-1][j] || dp[i][j-1]; }else{ dp[i][j]=(s[i-1]===p[j-1] || p[j-1]===‘?‘) && dp[i-1][j-1]; } } } return dp[m][n]; };
标签:letter sequence single cti inpu ike seq cas color
原文地址:https://www.cnblogs.com/xingguozhiming/p/10424936.html