码迷,mamicode.com
首页 > 编程语言 > 详细

python实现单例模式

时间:2019-03-03 22:14:27      阅读:194      评论:0      收藏:0      [点我收藏+]

标签:int   object   单例   singleton   单例模式   python   for   method   init   

#装饰器实现单例模式
def singleton1(func):
    instance={}
    def inner(*args,**kwargs):
        if func not in instance:
           instance[func]=func(*args,**kwargs)
        return instance[func]
    return inner
@singleton1
class user():
    pass
foo1=user()
foo2=user()
print(foo1 is foo2)
#使用修改基类实现单例模式
class Singleton2():
    def __new__(cls, *args, **kwargs):
        if not hasattr(cls, _instance):
            cls._instance = super().__new__(cls, *args, **kwargs)
        return cls._instance

class Foo(Singleton2):
    pass


foo3 = Foo()
foo4 = Foo()

print( foo3 is foo4)
#使用类实现单例模式,配合多线程
import threading
import time
class Singleton(object):
    _lock=threading.Lock()
    def __init__(self):
        time.sleep(1)

    @classmethod
    def instance(cls, *args, **kwargs):
        if not hasattr(Singleton, "_instance"):
            with Singleton._lock:
                if not hasattr(Singleton, "_instance"):
                    Singleton._instance = Singleton(*args, **kwargs)
        return Singleton._instance

def task(arg):
    obj = Singleton.instance()
    print(obj)

for i in range(10):
    t = threading.Thread(target=task,args=[i,])
    t.start()

time.sleep(20)
obj=Singleton.instance()
print(obj)
#使用元类实现单例模式
class SingletonType(type):
    _instance_lock = threading.Lock()
    def __call__(cls, *args, **kwargs):
        if not hasattr(cls, "_instance"):
            with SingletonType._instance_lock:
                if not hasattr(cls, "_instance"):
                    cls._instance = super(SingletonType,cls).__call__(*args, **kwargs)
        return cls._instance

class Foo(metaclass=SingletonType):
    def __init__(self,name):
        self.name = name


obj1 = Foo(name)
obj2 = Foo(name)
print(obj1 is obj2)

 

python实现单例模式

标签:int   object   单例   singleton   单例模式   python   for   method   init   

原文地址:https://www.cnblogs.com/lalalaxixixi/p/10467872.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!