标签：格式化输出 ati 执行 整型 其他 表达式 二进制 err 强制类型转换
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\n
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换行
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\t
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水平制表，跳到下一个tab
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\v
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垂直制表
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\b
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退格，当前位置移到前一列
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\r
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回车，将当前位置移到本行开头 |
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\f
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换页，将当前位置移到下一页开头
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\a
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响铃报警
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\0
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空字符，字符串结束符
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\\
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代表反斜杠
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\‘
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字符‘‘‘
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\"
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字符“
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\ddd
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1~3位八进制数字
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\xhh
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‘hh’1~2位十六进制数字
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void main() { int a,b; char ch1,ch2; }
# include <stdio.h> #include <string.h> void main() { int a,b,c,t; printf("please input 3 numbers:"); scanf("%d%d%d",&a,&b,&c); t=(a>b)?a:b; t=(t>c)?t:c; printf("%d",t); }
# include <stdio.h> #include <string.h> void main() { int a,b,c; printf("please input 3 numbers:"); scanf("%d%d%d",&a,&b,&c); if (a>b) printf("a is begger than b"); else printf("a is small than b"); } switch语句 switch(grade) ( case ‘A‘: printf("1");break; case ‘B‘: printf("2");break; default: printf("error");break; )
# include <stdio.h> void main() { float data1,data2,result; char op; scanf("inpurt 2 numbers %f and %f",&data1,&data2); scanf("inpurt operation %c", &op); switch(op) ( case‘+‘: result = data1 + data2; break; case‘-‘: result = data1 - data2; break; case‘*‘: result = data1 * data2; break; case‘/‘: result = data1 / data2; break; ) printf("result is %f", result); }
# include <stdio.h> void main() { int i=1,total=0; while (i<100) { total = total +i; i++; } printf("total is %d",total); }
do { fact = fact +i; i++; } while(i<=10); printf("nnn")
# include <stdio.h> void main() { int i,j,n; printf("pls enter th n value"); scanf("%d", &n); for (i=1;i<=n;i++) { for (j=1;j<=n-i;j++) { printf(" "); } for (j=1;j<=2*i-1;j++) { printf("*"); } printf("\n"); } }
# include <stdio.h> # define N 10 void main() { int i,max,a[N]; printf("pls key in 10 numbers"); for(i=0;i<N;i++) scanf("%d",&a[i]); max=0; for(i=1;i<N;i++) if(a[i]>a[max]) max = i; printf("%d",a[max]); }
# include <stdio.h> # define N 10 void main() { int i,a[N],j,k,t; printf("pls key in 10 numbers"); for (i=0;i<N;i++) scanf("%d",&a[i]); for (i=0;i<N-1;i++) for (j=0;j<N-i-1;j++) if (a[j]>a[j+1]) { t=a[j]; a[j] =a[j+1]; a[j+1]=t; } for(i=0;i<N;i++) printf("%d ",a[i]); } Z
标签：格式化输出 ati 执行 整型 其他 表达式 二进制 err 强制类型转换
原文地址：https://www.cnblogs.com/joe-zhang/p/10468768.html
