标签:rgs sem har dea foo delete 用两个 获得 地址
using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; namespace LinkedListTest { class Program { static void Main(string[] args) { LinkList<int> linkA = new LinkList<int>(); linkA.Append(1); linkA.Append(3); linkA.Append(5); linkA.Append(7); linkA.Append(9); LinkList<int> linkB = new LinkList<int>(); linkB.Append(0); linkB.Append(2); linkB.Append(4); linkB.Append(6); linkB.Append(8); //合并有序链表 Console.WriteLine("----------合并有序链表---------"); Node<int> nodeMerge= Merge(linkA.Head, linkB.Head); LinkList<int> linkMerge = new LinkList<int>(); linkMerge.Head = nodeMerge; linkMerge.Dispaly(); //链表反转 Console.WriteLine("----------链表反转---------"); linkMerge.Reverse(); Console.Read(); } /// <summary> /// 链表合并 /// </summary> /// <param name="nodeA"></param> /// <param name="nodeB"></param> /// <returns></returns> public static Node<int> Merge(Node<int> nodeA, Node<int> nodeB) { if (nodeA == null) { return nodeB; } else if (nodeB == null) { return nodeA; } Node<int> newHead = null; if (nodeA.Data <= nodeB.Data) { newHead = nodeA; newHead.Next = Merge(nodeA.Next, nodeB); } else { newHead = nodeB; newHead.Next = Merge(nodeA, nodeB.Next); } return newHead; } } public class LinkList<T> { public Node<T> Head { set; get; } //单链表头 //构造 public LinkList() { Clear(); } /// <summary> /// 求单链表的长度 /// </summary> /// <returns></returns> public int GetLength() { Node<T> p = Head; int length = 0; while (p != null) { p = p.Next; length++; } return length; } /// <summary> /// 判断单键表是否为空 /// </summary> /// <returns></returns> public bool IsEmpty() { if (Head == null) return true; else return false; } /// <summary> /// 清空单链表 /// </summary> public void Clear() { Head = null; } /// <summary> /// 获得当前位置单链表中结点的值 /// </summary> /// <param name="i">结点位置</param> /// <returns></returns> public T GetNodeValue(int i) { if (IsEmpty() || i < 1 || i > GetLength()) { Console.WriteLine("单链表为空或结点位置有误!"); return default(T); } Node<T> A = new Node<T>(); A = Head; int j = 1; while (A.Next != null && j < i) { A = A.Next; j++; } return A.Data; } /// <summary> /// 增加新元素到单链表末尾 /// </summary> public void Append(T item) { Node<T> foot = new Node<T>(item); Node<T> A = new Node<T>(); if (Head == null) { Head = foot; return; } A = Head; while (A.Next != null) { A = A.Next; } A.Next = foot; } /// <summary> /// 增加单链表插入的位置 /// </summary> /// <param name="item">结点内容</param> /// <param name="n">结点插入的位置</param> public void Insert(T item, int n) { if (IsEmpty() || n < 1 || n > GetLength()) { Console.WriteLine("单链表为空或结点位置有误!"); return; } if (n == 1) //增加到头部 { Node<T> H = new Node<T>(item); H.Next = Head; Head = H; return; } Node<T> A = new Node<T>(); Node<T> B = new Node<T>(); B = Head; int j = 1; while (B.Next != null && j < n) { A = B; B = B.Next; j++; } if (j == n) { Node<T> C = new Node<T>(item); A.Next = C; C.Next = B; } } /// <summary> /// 删除单链表结点 /// </summary> /// <param name="i">删除结点位置</param> /// <returns></returns> public void Delete(int i) { if (IsEmpty() || i < 1 || i > GetLength()) { Console.WriteLine("单链表为空或结点位置有误!"); return; } Node<T> A = new Node<T>(); if (i == 1) //删除头 { A = Head; Head = Head.Next; return; } Node<T> B = new Node<T>(); B = Head; int j = 1; while (B.Next != null && j < i) { A = B; B = B.Next; j++; } if (j == i) { A.Next = B.Next; } } /// <summary> /// 显示单链表 /// </summary> public void Dispaly() { Node<T> A = new Node<T>(); A = Head; while (A != null) { Console.WriteLine(A.Data); A = A.Next; } } #region 面试题 /// <summary> /// 单链表反转 /// </summary> public void Reverse() { if (GetLength() == 1 || Head == null) { return; } Node<T> NewNode = null; Node<T> CurrentNode = Head; Node<T> TempNode = new Node<T>(); while (CurrentNode != null) { TempNode = CurrentNode.Next; CurrentNode.Next = NewNode; NewNode = CurrentNode; CurrentNode = TempNode; } Head = NewNode; Dispaly(); } /// <summary> /// 获得单链表中间值 /// 思路:使用两个指针,第一个每次走一步,第二个每次走两步: /// </summary> public void GetMiddleValue() { Node<T> A = Head; Node<T> B = Head; while (B != null && B.Next != null) { A = A.Next; B = B.Next.Next; } if (B != null) //奇数 { Console.WriteLine("奇数:中间值为:{0}", A.Data); } else //偶数 { Console.WriteLine("偶数:中间值为:{0}和{1}", A.Data, A.Next.Data); } } #endregion } public class Node<T> { public T Data { set; get; } //数据域,当前结点数据 public Node<T> Next { set; get; } //位置域,下一个结点地址 public Node(T item) { this.Data = item; this.Next = null; } public Node() { this.Data = default(T); this.Next = null; } } }
标签:rgs sem har dea foo delete 用两个 获得 地址
原文地址:https://www.cnblogs.com/youngharvard/p/10494503.html