Garlands CodeForces - 707E (离线树状数组)

#include <iostream>
#include <algorithm>
#include <cstdio>
#include <math.h>
#include <set>
#include <map>
#include <queue>
#include <string>
#include <string.h>
#include <bitset>
#define REP(i,a,n) for(int i=a;i<=n;++i)
#define PER(i,a,n) for(int i=n;i>=a;--i)
#define hr putchar(10)
#define pb push_back
#define lc (o<<1)
#define rc (lc|1)
#define mid ((l+r)>>1)
#define ls lc,l,mid
#define rs rc,mid+1,r
#define x first
#define y second
#define io std::ios::sync_with_stdio(false)
#define endl ‘\n‘
using namespace std;
typedef long long ll;
typedef pair<int,int> pii;
const int P = 1e9+7, INF = 0x3f3f3f3f;
ll gcd(ll a,ll b) {return b?gcd(b,a%b):a;}
ll qpow(ll a,ll n) {ll r=1%P;for (a%=P;n;a=a*a%P,n>>=1)if(n&1)r=r*a%P;return r;}
ll inv(ll x){return x<=1?1:inv(P%x)*(P-P/x)%P;}
//head




const int N = 2e3+20, M = 1e6+10;
int n, m, k, q, cnt;
int len[N], x[N][N], y[N][N], w[N][N], vis[N];
char op[M][10];
int t[M], t1[N], t2[N], t3[N], t4[N];
ll c[N][N], ans[N][N];
void upd(int x, int y, int w) {
	for (int i=x; i<=n+1; i+=i&-i) for (int j=y; j<=m+1; j+=j&-j) c[i][j]+=w;
}
ll qry(int x, int y) {
	ll r = 0;
	for (int i=x; i; i^=i&-i) for (int j=y; j; j^=j&-j) r+=c[i][j];
	return r;
}

int main() {
	scanf("%d%d%d", &n, &m, &k);
	REP(i,1,k) {
		scanf("%d", len+i);
		REP(j,1,len[i]) { 
			scanf("%d%d%d",&x[i][j],&y[i][j],&w[i][j]);
			++x[i][j], ++y[i][j];
		}
	}
	scanf("%d", &q);
	REP(i,1,q) {
		scanf("%s", op[i]);
		if (op[i][0]==‘S‘) scanf("%d",t+i);
		else { 
			++cnt;
			scanf("%d%d%d%d",t1+cnt,t2+cnt,t3+cnt,t4+cnt);
			++t1[cnt],++t2[cnt],++t3[cnt],++t4[cnt];
		}
	}
	REP(i,1,k) {
		REP(j,1,len[i]) upd(x[i][j],y[i][j],w[i][j]);
		REP(j,1,cnt) {
			int x1=t1[j],y1=t2[j],x2=t3[j],y2=t4[j];
			ans[i][j] = qry(x2,y2)-qry(x2,y1-1)-qry(x1-1,y2)+qry(x1-1,y1-1);
		}
		REP(j,1,len[i]) upd(x[i][j],y[i][j],-w[i][j]);
	}
	int now = 0;
	REP(i,1,q) {
		if (op[i][0]==‘S‘) vis[t[i]] ^= 1;
		else {
			++now;
			ll r = 0;
			REP(i,1,k) if (!vis[i]) r+=ans[i][now];
			printf("%lld\n", r);
		}
	}
}