标签:names info stat sel img 集合 lam type color
一个简单的列子,需要把一个集合的数据添加到数据库中。
我先这样写了,然后报错了
public async Task<IHttpActionResult> Test([FromUri]string name = "") { List<string> strList = new List<string>() { "测试", "测试1", "测试2", "测试3", "测试4", "测试5", "测试6", "测试7", "测试8" }; strList.ForEach(async x => { JkSystemname jk = await dbOracle.JkSystemnames.AsQueryable().FirstAsync(ee => ee.Name == x); if (jk == null) { jk = new JkSystemname() { Name = x }; dbOracle.JkSystemnames.Insert(jk); } }); return await Task.FromResult(Ok(new { errcode = 0, errmag = "success" })); }
两个办法解决循环里面不能使用异步
①把方法提出来,然后返回task,然后一起执行,这样不会按顺序执行
public async Task<IHttpActionResult> Test([FromUri]string name = "") { List<string> strList = new List<string>() { "测试", "测试1", "测试2", "测试3", "测试4", "测试5", "测试6", "测试7", "测试8" }; IEnumerable<Task> tasks = strList.Select(x => TestAsync(x));//映射到一个可以遍历的task await Task.WhenAll(tasks); //使用task.whenall 完成 return await Task.FromResult(Ok(new { errcode = 0, errmag = "success" })); } /// <summary> /// 根据传入的名称,返回需要执行的task代码 /// </summary> /// <param name="name"></param> /// <returns></returns> public async Task TestAsync(string name) { JkSystemname jk = await dbOracle.JkSystemnames.AsQueryable().FirstAsync(ee => ee.Name == name); if (jk == null) { jk = new JkSystemname() { Name = name }; dbOracle.JkSystemnames.Insert(jk); } }
②扩展方法,一个个的执行
/// <summary> /// 使用异步遍历处理数据 /// </summary> /// <typeparam name="T">需要遍历的基类</typeparam> /// <param name="list">集合</param> /// <param name="func">Lambda表达式</param> /// <returns></returns> public static async Task ForEachAsync<T>(this List<T> list, Func<T, Task> func) { foreach (T value in list) { await func(value); } }
public async Task<IHttpActionResult> Test([FromUri]string name = "") { List<string> strList = new List<string>() { "测试", "测试1", "测试2", "测试3", "测试4", "测试5", "测试6", "测试7", "测试8" }; //①先得到集合,然后一起执行 //IEnumerable<Task> tasks = strList.Select(x => TestAsync(x));//映射到一个可以遍历的task //await Task.WhenAll(tasks); //使用task.whenall 完成 //②一步一步的循环 await strList.ForEachAsync<string>(async x => { JkSystemname jk = await dbOracle.JkSystemnames.AsQueryable().FirstAsync(ee => ee.Name == x); if (jk == null) { jk = new JkSystemname() { Name = x }; dbOracle.JkSystemnames.Insert(jk); } }); return await Task.FromResult(Ok(new { errcode = 0, errmag = "success" })); }
标签:names info stat sel img 集合 lam type color
原文地址:https://www.cnblogs.com/Sea1ee/p/10624769.html