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java多线程2

时间:2019-04-10 00:36:26      阅读:158      评论:0      收藏:0      [点我收藏+]

标签:生产   wait   getname   over   命令   products   ack   dom   i++   

今日大部分时间花在了C语言的链表上了,以下是我今日所学习的java多线程内容,今天学习的是多线程里的其他命令,wait,notify,nofityAll,分别是等待,唤醒,全部唤醒。

附今日敲的代码:

 1 package com.wsy.product;
 2 
 3 public class Product {
 4     private int id;
 5     private String name;
 6     public Product(int id, String name) {
 7         this.id = id;
 8         this.name = name;
 9     }
10     @Override
11     public String toString() 
12     {
13         return "("+"产品id"+id+")"+"    "+"("+"产品名:"+name+")";
14     }
15     public int getId() {
16         return id;
17     }
18     public void setId(int id) {
19         this.id = id;
20     }
21     public String getName() {
22         return name;
23     }
24     public void setName(String name) {
25         this.name = name;
26     }
27     
28     
29 
30 }
 1 package com.wsy.product;
 2 
 3 public class Storage {
 4     //仓库的总容量为10
 5     private Product[] products = new Product[10];
 6     private int count = 0;
 7     //生产者将产品放入仓库
 8     public synchronized void push(Product product) 
 9     {
10         //如果条件满足表示仓库已经满了
11         while(count == products.length) 
12         {
13             try {
14                 System.out.println("producer wait!");
15                 wait();
16             } catch (InterruptedException e) {
17                 // TODO Auto-generated catch block
18                 e.printStackTrace();
19             }
20         }
21         //将产品放入仓库
22         products[count++] = product ;
23         System.out.println(Thread.currentThread().getName()+"    "+"生产了"+product);
24         //将所有线程唤醒
25         System.out.println("notifyAll!");
26         notifyAll();
27     }
28     //消费者将产品拿出仓库
29     public synchronized void pop() 
30     {
31         //count等于0代表仓库现在为空 需要等待生产者生产
32         while(count == 0 ) 
33         {
34             try {
35                 System.out.println("consumer wait!");
36                 wait();
37             } catch (InterruptedException e) {
38                 // TODO Auto-generated catch block
39                 e.printStackTrace();
40             }
41         }
42         count--;
43         Product product = products[count];
44         products[count] = null;
45         System.out.println(Thread.currentThread().getName()+"    "+"消费了"+product);
46         //将所有线程唤醒
47         System.out.println("notifyAll!");
48         notifyAll();
49     }
50 }
 1 package com.wsy.product;
 2 
 3 public class Consumer implements Runnable {
 4     private Storage storage;
 5     public Consumer(Storage storage) 
 6     {
 7         this.storage = storage;
 8     }
 9     public void run() 
10     {
11         int i = 0;
12         while(i<10)
13         {
14             i++;
15             storage.pop();
16 
17         }
18     }
19 }
 1 package com.wsy.product;
 2 
 3 import java.util.Random;
 4 
 5 public class Producer implements Runnable {
 6     private Storage storage;
 7     public Producer(Storage storage)
 8     {
 9         this.storage = storage;
10     }
11     @Override
12     public void run() 
13     {
14         int i =0;
15         Random r = new Random();
16         while(i<10)
17         {
18             i++;
19             Product product = new Product(i , "序号"+Integer.toString(r.nextInt(100)));
20             storage.push(product);
21         }
22     }
23     
24 
25 }
 1 package com.wsy.product;
 2 /**
 3  * 经典生产者与消费者问题
 4  * 生产者不断的往仓库中存放产品,消费者从仓库中消费产品。
 5  * 其中生产者和消费者都可以有若干个。
 6  * 仓库规则:容量有限,库满时不能存放,库空时不能取产品 。
 7  */
 8 public class ProductTest {
 9 
10     public static void main(String[] args) {
11         Storage storage = new Storage();
12         Thread consumer1 = new Thread(new Consumer(storage));
13         consumer1.setName("消费者1");
14         Thread consumer2 = new Thread(new Consumer(storage));
15         consumer2.setName("消费者2");
16         Thread producer1 = new Thread(new Producer(storage));
17         producer1.setName("生产者1");
18         Thread producer2 = new Thread(new Producer(storage));
19         producer2.setName("生产者2");
20         producer1.start();
21         producer2.start();
22         try {
23             Thread.sleep(100);
24         } catch (InterruptedException e) {
25             // TODO Auto-generated catch block
26             e.printStackTrace();
27         }
28         consumer1.start();
29         consumer2.start();
30         
31     }
32 
33 }

 

java多线程2

标签:生产   wait   getname   over   命令   products   ack   dom   i++   

原文地址:https://www.cnblogs.com/sucker/p/10680766.html

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