标签：++ 习题 nbsp pac imp 练习 public code count
1.将一个给定的整型数组转置输出，
例如： 源数组，1 2 3 4 5 6
转置之后的数组，6 5 4 3 2 1
package Array; public class arrayTest1 { public static void main(String[] args) { int[] a={1,2,3,4,5,6}; int m=a.length; int temp; for (int i = 0; i <m/2; i++) { temp=a[i]; a[i]=a[m-i-1]; a[m-i-1]=temp; } for (int i = 0; i < m; i++) { System.out.print(a[i]+" "); } } }
2.现在有如下的一个数组：
int[] oldArr = {1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5} ;
要求将以上数组中值为0的项去掉，将不为0的值存入一个新的数组，生成的新数组为：
int[] newArr = {1,3,4,5,6,6,5,4,7,6,7,5} ;
package Array; public class arrayTest2 { public static void main(String[] args) { int[] oldArr = {1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5} ; int count=0; for (int i = 0; i <oldArr.length ; i++) { if(oldArr[i]!=0){ count++; } } int[] newArr=new int[count]; for (int i = 0,j=0; i <oldArr.length ; i++) { if(oldArr[i]!=0) { newArr[j]=oldArr[i]; j++; } } System.out.print("新数组为："); for (int i = 0; i < count; i++) { System.out.print(newArr[i]+" "); } } }
3.现在给出两个数组：
数组a："1,7,9,11,13,15,17,19"
数组b："2,4,6,8,10"
两个数组合并为数组c。
package Array; import java.util.ArrayList; import java.util.List; public class arrayTest3 { public static void main(String[] args) { int[] a = {1, 7, 9, 11, 13, 15, 17, 19}; int[] b = {2, 4, 6, 8, 10}; int m = a.length + b.length; int j = 0,temp; int[] c = new int[m]; for (int i = 0; i < a.length; i++) { c[i] = a[i]; } for (int i = a.length; i < m; i++) { c[i] = b[j]; j++; } for(int i=0;i<m-1;i++){ for(int s=0;s<m-1-i;s++){ if(c[s]>c[s+1]){ temp=c[s]; c[s]=c[s+1]; c[s+1]=temp; } } } for (int i = 0; i < m; i++) { System.out.print(c[i] + " "); } } }
标签：++ 习题 nbsp pac imp 练习 public code count
原文地址：https://www.cnblogs.com/almm/p/10755426.html
