标签:ted als imp 数组 使用 char output bsp solution
Roman numerals are represented by seven different symbols: I
, V
, X
, L
, C
, D
and M
.
Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000
For example, two is written as II
in Roman numeral, just two one‘s added together. Twelve is written as, XII
, which is simply X
+ II
. The number twenty seven is written as XXVII
, which is XX
+ V
+ II
.
Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII
. Instead, the number four is written as IV
. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX
. There are six instances where subtraction is used:
I
can be placed before V
(5) and X
(10) to make 4 and 9. X
can be placed before L
(50) and C
(100) to make 40 and 90. C
can be placed before D
(500) and M
(1000) to make 400 and 900.Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999.
Example 1:
Input: 3 Output: "III"
Example 2:
Input: 4 Output: "IV"
Example 3:
Input: 9 Output: "IX"
Example 4:
Input: 58 Output: "LVIII" Explanation: L = 50, V = 5, III = 3.
Example 5:
Input: 1994 Output: "MCMXCIV" Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.
class Solution { public String intToRoman(int num) { int len; String str=""; int[] val = {1000,500,100,50,10,5,1}; char[] sym = {‘M‘,‘D‘,‘C‘,‘L‘,‘X‘,‘V‘,‘I‘}; for(int i = 0; i < val.length; i+=2){ len = num/val[i]; if(len <=3 ){ //0-3 for(int j = 0; j < len; j++){ str += sym[i]; } } else if(len == 4){ //4 str = str + sym[i] + sym[i-1]; } else if(len <= 8){ //5-8 str += sym[i-1]; for(int j = 5; j < len; j++){ str += sym[i]; } } else{ //9 str = str + sym[i] + sym[i-2]; } num %= val[i]; } return str; } }
解题思路:
使用两个对应的数组,以减少代码的重复量
标签:ted als imp 数组 使用 char output bsp solution
原文地址:https://www.cnblogs.com/qionglouyuyu/p/10768895.html