标签:current dex thread red and new clear ace net
wait(), notify()和notifyAll()方法用于在线程间建立关联. 在对象上调用wait()将使线程进入WAITTING状态, 直到其他线程对同一个对象调用notify()或notifyAll(). 在任何线程上, 对一个对象调用wait(), notify()和notifyAll(), 都需要先获得这个对象的锁, 就是说, 这些方法必须在synchronized方法或代码块中调用.
调用notify()时, 在所有WAITING状态的线程中只会有一个线程被通知, 这个选择是随机的, 被通知的线程并不会立即得到对象的锁, 而是一直等到调用notify()的线程释放锁, 在这之前线程都是BLOCKED状态. 当获得锁后, 就会从BLOCKED状态变为RUNNING状态. 例子
class Shared { synchronized void waitMethod() { Thread t = Thread.currentThread(); System.out.println(t.getName() + " is releasing the lock and going to wait"); try { wait(); } catch (InterruptedException e) { e.printStackTrace(); } System.out.println(t.getName() + " has been notified and acquired the lock back"); } synchronized void notifyOneThread() { Thread t = Thread.currentThread(); notify(); System.out.println(t.getName() + " has notified one thread waiting for this object lock"); } } public class MainClass { public static void main(String[] args) { final Shared s = new Shared(); //Thread t1 will be waiting for lock of object ‘s‘ Thread t1 = new Thread() { @Override public void run() { s.waitMethod(); } }; t1.start(); //Thread t2 will be waiting for lock of object ‘s‘ Thread t2 = new Thread() { @Override public void run() { s.waitMethod(); } }; t2.start(); //Thread t3 will be waiting for lock of object ‘s‘ Thread t3 = new Thread() { @Override public void run() { s.waitMethod(); } }; t3.start(); try { Thread.sleep(1000); } catch (InterruptedException e) { e.printStackTrace(); } //Thread t4 will notify only one thread which is waiting for lock of object ‘s‘ Thread t4 = new Thread() { @Override public void run() { s.notifyOneThread(); } }; t4.start(); } }
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当线程在对象上调用notifyAll()时, 所有WAITING状态的线程都会被通知, 所有的线程都会从WAITING状态变成BLOCKED状态, 然后争抢对象的锁. 得到对象锁的线程, 将变成RUNNING状态, 而其他线程则继续保持BLOCKED状态继续等待获取对象锁. 例子
class Shared { synchronized void waitMethod() { Thread t = Thread.currentThread(); System.out.println(t.getName() + " is releasing the lock and going to wait"); try { wait(); } catch (InterruptedException e) { e.printStackTrace(); } System.out.println(t.getName() + " has been notified and acquired the lock back"); } synchronized void notifyAllThread() { Thread t = Thread.currentThread(); notifyAll(); System.out.println(t.getName() + " has notified all threads waiting for this object lock"); } } public class MainClass { public static void main(String[] args) { final Shared s = new Shared(); //Thread t1 will be waiting for lock of object ‘s‘ Thread t1 = new Thread() { @Override public void run() { s.waitMethod(); } }; t1.start(); //Thread t2 will be waiting for lock of object ‘s‘ Thread t2 = new Thread() { @Override public void run() { s.waitMethod(); } }; t2.start(); //Thread t3 will be waiting for lock of object ‘s‘ Thread t3 = new Thread() { @Override public void run() { s.waitMethod(); } }; t3.start(); try { Thread.sleep(1000); } catch (InterruptedException e) { e.printStackTrace(); } //Thread t4 will notify all threads which are waiting for lock of object ‘s‘ Thread t4 = new Thread() { @Override public void run() { s.notifyAllThread(); } }; t4.start(); } }
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一个生产者和消费者的例子
注意, 在1个生产1个消费的情况下, 是能确保生产和消费的互相通知的, 但是在2个生产1个消费的情况下, 有可能要多次notify后消费线程才能拿到queue的锁.
public class DemoThreadWait1 { Queue<Integer> queue = new LinkedList<>(); public void consume() { synchronized (queue) { while (queue.isEmpty()) { try { System.out.println("consume wait"); queue.wait(); } catch (InterruptedException e) { e.printStackTrace(); } System.out.println("remove all"); queue.clear(); queue.notify(); } } } public void produce(int i) { synchronized (queue) { if (queue.size() < 5) { System.out.println("add " + i); queue.add(i); } if (queue.size() >= 5) { queue.notify(); try { System.out.println("produce wait"); queue.wait(); } catch (InterruptedException e) { e.printStackTrace(); } } } } public static void main(String[] args) { DemoThreadWait1 demo = new DemoThreadWait1(); new Thread(()->{ while(true) { demo.consume(); } }).start(); new Thread(()->{ while(true) { demo.produce((int) (Math.random() * 1000)); } }).start(); new Thread(()->{ while(true) { demo.produce((int) (Math.random() * 1000)); } }).start(); } }
Java线程的wait(), notify()和notifyAll()
标签:current dex thread red and new clear ace net
原文地址:https://www.cnblogs.com/milton/p/10884427.html