标签:rar get class abc art print else ring mat
//java
public class KMP {
public static int[] getNextArray(char[] t) {
int[] next = new int[t.length];
next[0] = -1;
next[1] = 0;
int k;
for (int j = 2; j < t.length; j++) {
k=next[j-1];
while (k!=-1) {
if (t[j - 1] == t[k]) {
next[j] = k + 1;
break;
}
else {
k = next[k];
}
next[j] = 0; //当k==-1而跳出循环时,next[j] = 0,否则next[j]会在break之前被赋值
}
}
return next;
}
public static int kmpMatch(String s, String t){
char[] s_arr = s.toCharArray();
char[] t_arr = t.toCharArray();
int[] next = getNextArray(t_arr);
int i = 0, j = 0;
while (i<s_arr.length && j<t_arr.length){
if(j == -1 || s_arr[i]==t_arr[j]){
i++;
j++;
}
else
j = next[j];
}
if(j == t_arr.length)
return i-j;
else
return -1;
}
public static void main(String[] args) {
System.out.println(kmpMatch("abcabaabaabcacb", "abaabcac"));
}
}
//c++
#include <iostream>
#include <string>
using namespace std;
int next[8];
/*求单个回溯值
int GetNext(int j,char T[])
{
if(j==0) return -1;
if(j>0)
{
int k=GetNext(j-1,T);
while (k>=0)
if(T[j-1]==T[k]) return k+1;
else k=GetNext(k,T);
return 0;
}
return 0;
}*/
void GetNext(char T[])
{
int j=0,k=-1;next[j]=k;
while (T[j]!=‘\0‘)
if(k==-1 || T[j]==T[k])
{j=j+1;k=k+1;next[j]=k;}
else k=next[k];
}
int KMP(char S[],int start,char T[])
{ int i=start,j=0;
while (S[i]!=‘\0‘&&T[j]!=‘\0‘)
if(j==-1||S[i]==T[j])
{i=i+1;j=j+1;}
else j=next[j];
if(T[j]==‘\0‘) return(i-j);
else return(-1);
}
int main()
{ //字符数组检测不到"\0"
//char S[]={‘d‘,‘f‘,‘g‘,‘a‘,‘b‘,‘a‘,‘a‘,‘b‘,‘c‘,‘a‘,‘c‘,‘f‘};
//char T[]={‘a‘,‘b‘,‘a‘,‘a‘,‘b‘,‘c‘,‘a‘,‘c‘};
char S[]="gfylaa45e4daabaabcac";
char T[]="abaabcac";
GetNext(T);
for(int i=0;i<8;i++)
cout<<next[i]<<‘ ‘;
cout<<endl;
cout<<KMP(S,0,T)<<endl;
return 0;
}
标签:rar get class abc art print else ring mat
原文地址:https://www.cnblogs.com/cky-2907183182/p/10885441.html