标签:style blog io os ar 使用 java for strong
一、LinkedHashMap集合
import java.util.HashMap; import java.util.Iterator; import java.util.LinkedHashMap; import java.util.Map; public class Main { public static void main(String[] args) { HashMap<Integer, String> hm = new LinkedHashMap<Integer,String>();//保证有序 hm.put(1, "a"); hm.put(5, "c"); hm.put(3, "e"); hm.put(4, "s"); Iterator<Map.Entry<Integer,String>> It = hm.entrySet().iterator(); while(It.hasNext()){ Map.Entry<Integer, String> meEntry = It.next(); Integer key = meEntry.getKey(); String value = meEntry.getValue(); System.out.println("key - value :"+key+"-"+value); } } }
记录字母出现次数
import java.util.Iterator; import java.util.Map; import java.util.TreeMap; /*"as6&dg+dfg-badf453sasxa" 记录字符串中字母出现的次数 a(4)b(1) d(4)... * * 思路: * 很容易发现,字母和次数之间存在对应关系,而且需要存储 * 能存储映射关系的集合有数组和Map * 判断关系中的一方是否是有序编号?否 * 需要使用Map集合 * 判断具备唯一性的一方具备着顺序如a,b,c。。。 * 所以使用TreeMap * */ public class Main { public static void main(String[] args) { /* * 1.将字符串变成单个字母的字符数组 * 2.用每个字母当中键去查Map集合的表 * 3.判断字母是否存在,不存在按 字母<key> - time<value>的方式存储 (初始time = 1) * 存在,按 字母<key> - ++time<value>的方式存储 * */ String str = "asdgdfgbadfsasxa"; String result = Get(str); System.out.println(result); } public static String Get(String str){ char[] ch = str.toCharArray(); Map<Character,Integer> map = new TreeMap<Character,Integer>(); for (int i = 0; i < ch.length; i++) { if(!('a'<=ch[i]&&ch[i]<='z' || 'A'<=ch[i]&&ch[i]<='Z')) continue; Integer value = map.get(ch[i]); //将字母作为键查表 int time = 1; if(value!=null) time = value + 1; map.put(ch[i], time); } return Map_To_String(map); } private static String Map_To_String(Map map) { StringBuilder str = new StringBuilder(); Iterator<Character> it = map.keySet().iterator(); while(it.hasNext()){ Character key = it.next(); Integer value = (Integer) map.get(key); str.append(key+"("+value+")"); } return str.toString(); } }
二、Map集合查表法
import java.util.HashMap; import java.util.Iterator; import java.util.Map; import java.util.Scanner; import java.util.TreeMap; import javax.management.RuntimeErrorException; public class Main { public static void main(String[] args) { /*在查表法中Map集合的应用较多*/ int num; Scanner in = new Scanner(System.in); num = in.nextInt(); String week = Get_Week(num-1); System.out.println(week); System.out.println(Get_Week_English(week)); in.close(); } public static String Get_Week(int num){ if (num>7 || num <0) throw new RuntimeException("输入错误"); String[] week = {"星期一","星期二","星期三","星期四","星期五","星期六","星期天"}; return week[num]; } public static String Get_Week_English(String week){ Map<String, String> map = new HashMap<String, String>(); if(!(week.equals("星期一")||week.equals("星期二")||week.equals("星期三") ||week.equals("星期四")||week.equals("星期五")||week.equals("星期六")||week.equals("星期天"))) { throw new RuntimeException("输入错误的星期"); } map.put("星期一", "Monday");//特别注意一点,map.put("",Set<Integer>);集合中也可以放集合 map.put("星期二", "Tus"); map.put("星期三", "Wes"); map.put("星期四", "Thu"); map.put("星期五", "Fri"); map.put("星期六", "Sta"); map.put("星期天", "Sun"); return map.get(week); } }
标签:style blog io os ar 使用 java for strong
原文地址:http://blog.csdn.net/wjw0130/article/details/40350599