标签:else string with 实现 Fix flight bre example 开始
一、题目Write a function to find the longest common prefix string amongst an array of strings.
If there is no common prefix, return an empty string "".
Example 1:
Input: ["flower","flow","flight"]
Output: "fl"
Example 2:
Input: ["dog","racecar","car"]
Output: ""
Explanation: There is no common prefix among the input strings.
Note:All given inputs are in lowercase letters a-z.
1、获取数组的第一个元素firstStr作为比较的对象;
2、以firstStr的长度作为条件设定while循环;
3、从数组第二个元素开始遍历数组,判断每个元素是否已firstStr作为前缀;
4、如果不是,则截掉firstStr最后一个字符,再重新遍历数组进行比较。
public String longestCommonPrefix(String[] strs) {
if (strs.length == 0) { // 当数组长度为0时,返回空
return "";
} else if (strs.length == 1) { // 当数组只有一个元素时,则返回该元素
return strs[0];
} else {
String firstStr = strs[0];
while (firstStr.length() != 0) {
for (int i = 1; i < strs.length; i++) {
if (strs[i].startsWith(firstStr)) {
if (i == strs.length -1) {
return firstStr;
}
continue;
} else {
// 从后往前一个一个截取
firstStr = firstStr.substring(0, firstStr.length() - 1);
break;
}
}
}
}
return "";
}
标签:else string with 实现 Fix flight bre example 开始
原文地址:https://blog.51cto.com/13666674/2400445