高级的模板可以修改string.Template的默认语法，为此需要调整它在模板中查找变量名所使用的正则表达式。
#############################################################
#test about matetrans()
leet = string.maketrans('asdfghjk', '12345678')
print s.translate(leet)
print s
#############################################################
#test about Template()
values = {'var':'foo'}
t=string.Template("""
Variable : $var
Escape : $$
Variable in text: ${var}iable
""")
print 'TEMPLATE:', t.substitute(values)
s="""
Variable : %(var)ss
Escape : %%
Variable in text: %(var)sssssiable
"""
print 'INTERPOLATION:', s%values
import re
print '-'*30
#about regular expression search()
pattern = 'this'
text='Does this text match the pattern?'
match = re.search(pattern, text)
s=match.start()
e=match.end()
print 'Dound "%s" \nin "%s" \nfrom %d to %d ("%s")' % (match.re.pattern,match.string,s,e,text[s:e])
#start()和end()方法可以给出字符串中相应的索引。print '-'*30
#about the Compile()
regexes=[re.compile(p)
for p in ['this','that']
]
text='Does this text match the pattern?'
print 'Text: %r\n' % text
for regex in regexes:
print 'seeking "%s" ->' % regex.pattern
if regex.search(text):
print 'match!'
else:
print 'no match!'
print '-'*30
#about the findall()
text = 'bbbbbababbababbabbbaba'
pattern = 'ba'
for match in re.findall(pattern, text):
print match
print '-'*30
#about the finditer()
#finditer会返回一个迭代器，可以生成match实例，而不像findall()是直接返回的字符串。
text='aaaadaaaaadadadada'
pattern='da'
for match in re.finditer(pattern,text):
s=match.start()
e=match.end()
print 'Found "%s" at %d:%d' % (text[s:e],s,e)
print '-'*30
#一种iterall()的不太高效的实现方式。
text='this is some text -- with punctuation.'
pattern=re.compile(r'\b\w*is\w*\b')
print 'text:', text
pos=0
while True:
match=pattern.search(text,pos)
print match
if not match:
break
s=match.start()
e=match.end()
print s,e
print '%d: %d = "%s"' % (s,e-1,text[s:e])
pos=e
原文地址：http://blog.csdn.net/ling1510/article/details/40380269
