c++练习—实现简单的4则运算

#pragma once
class Counter
{
public:
    void setExp(const char* exp);//设置表达式
    void cleanExp(); //清除表达式
    void countExp();//计算表达式
    int reExp();//返回结果

private:
    char m_exp[20];
    int m_Num1;
    int m_Num2;
    int sum;
    void sub(int n);//整理表达式，分离两个两个运算数
};

#include "Counter.h"
#include <string.h>
#include <stdlib.h>
void Counter::setExp(const char* exp)
{
    strcpy_s(m_exp, 20, exp);
}
void Counter::sub(int n)
{
    char num1[20];
    char num2[20];
    int len=strlen(m_exp);
    for (int i=0;i<len;i++)
    {
        if (i<n)
        {
            num1[i] = m_exp[i];
        }
        if (i>n)
        {
            num2[i - n-1] = m_exp[i];
        }
    }
    m_Num1 = atoi(num1);
    m_Num2 = atoi(num2);
}
void Counter::cleanExp()
{
    strcpy_s(m_exp, 20, 0);
}
void Counter::countExp()
{
    for (int i=0;i<20;i++)
    {
        switch (m_exp[i])
        {
        case ‘+‘: 
        {
            sub(i);
            sum = m_Num1 + m_Num2;
        }break;
        case ‘-‘: {
            sub(i);
            sum = m_Num1 - m_Num2;
        } break;
        case ‘*‘: {
            sub(i);
            sum = m_Num1 * m_Num2;
        } break;
        case ‘/‘: {
            sub(i);
            sum = m_Num1 / m_Num2;
        } break;
        default:
            break;
        }
    }
}
int Counter::reExp()
{
    return sum;
}