标签:art index lin extend sort div class 对象 rev
‘‘‘ #list的增删查改及其排序 #列表的增 list=["hello","Linda",13,"welcome","to","China"] #list的增 a=list.append("Chichy")#增加字符串 print(list) b=list.append(123)#增加数字 print(list) c=list.append([1,2,3,4])#增加列表 print(list) d=list.append((1,"hi",8))#增加元组 print(list) e=list.append({1:"one",2:"two"})#增加字典 print(list) #列表的插入 list=["hello","Linda",13,"welcome","to","China"] a=list.insert(56,"hi")#在要插入的内容后面写上索引,再把要插入的内容写在后面 print(list) b=list.insert(1,{1,2,3}) print(list) list=["hello","Linda",13,"welcome"] c=list.extend("China")#会把字符串拆解成由字符组成的字符串 print(list)#[‘hello‘, ‘Linda‘, 13, ‘welcome‘, ‘C‘, ‘h‘, ‘i‘, ‘n‘, ‘a‘] d=list.extend([1,2,3])#z这样添加到列表的是数字,int 属于不可迭代对象,而extend需要的是可迭代对象 print(list) #列表的删 pop 可以按照索引去删,也可以不写索引,但默认删除最后一个 list=["hello","Linda",13,"welcome"] a=list.pop(2) print(list) b=list.pop() print(list) >>> list=["hello","Linda",13,"welcome"] >>> list.pop(1) ‘Linda‘ #把要删除的元素返回 >>> print(list) [‘hello‘, 13, ‘welcome‘] >>> list.pop()#要么写一个参数,要么不写,不能写多个参数 ‘welcome‘ >>> print(list) [‘hello‘, 13] #列表的删 remove 按元素去删除 list=["hello","Linda",13,"welcome"] a=list.remove("hello")#删除字符串hello,若被删除字符串没有在列表中。则会出错 print(list) #列表的删 del 可以按照索引去删,也可以用切片去删 list=["hello","Linda",13,"welcome"] del list[-1] print(list) del list[2:] print(list) del list[0:] print(list) #result #[‘hello‘, ‘Linda‘, 13] #[‘hello‘, ‘Linda‘] #[] #列表的清空 clear clear不需要参数 list=["hello","Linda",13,"welcome"] a=list.clear() print(list)#[] #列表的查 list=["hello","Linda",13,"welcome"] print(list[0:])#查看列表中的元素 for i in list: print(i) #列表的改 list=["hello","Linda",13,"welcome"] list[0]="Hello" print(list)#[‘Hello‘, ‘Linda‘, 13, ‘welcome‘] list[0:2]="Good" #若需要给两个元素,你只给了一个,那么将会把第一个元素拆解成都单个字符组成的字符串 print(list)#[‘G‘, ‘o‘, ‘o‘, ‘d‘, 13, ‘welcome‘] list=["hello","Linda",13,"welcome"] list[0:2]="GOOD","smart" print(list)#[‘GOOD‘, ‘smart‘, 13, ‘welcome‘] #####列表中只有index,而字符串中有find 和index,find返回查找元素的索引,没有 ###查找到就返回-1,而index查找不到就报错。 #列表的排序 #sort 把例表里面的数按照从小到大的顺序排序 a=[1,4,2,6,3,5] #a1=a.sort(reverse=False) #与a.sort()等价 a1=a.sort()#[1, 2, 3, 4, 5, 6] print(a) #sort(reverse=True) 把列表里面的数字从大到小排序 a2=a.sort(reverse=True) print(a)#[6, 5, 4, 3, 2, 1] #reverse() 把列表里面的数字的排序恢复成一开始的序列 a3=a.reverse() print(a)#[1, 2, 3, 4, 5, 6]
标签:art index lin extend sort div class 对象 rev
原文地址:https://www.cnblogs.com/GZ1215-228513-Chichy/p/11286044.html