标签:long i++ define can src har main scan mamicode
分析
代码
#include<bits/stdc++.h>
using namespace std;
#define int long long
const int inf =1e18;
char s[1000100];
int a[1000100],pre[1000100],sur[1000100],mn[1000100];
signed main(){
int n,m,p,q,i,j,k,x,y,Ans=inf;
cin>>n>>p>>q>>x>>y;
scanf("%s",s+1);
for(i=1;i<=n;i++)a[i]=(s[i]==‘-‘?-1:1);
for(i=1;i<=n;i++)pre[i]=pre[i-1]+a[i];
for(i=1;i<=n;i++)mn[i]=min(mn[i-1],pre[i]);
k=(q-p-pre[n])/2;
for(i=1;i<=n;i++){
int sum=min(pre[n]-pre[n-i+1]+mn[n-i+1],sur[i-1]);
int t=max(0ll,(-p-sum+1)/2);
Ans=min(Ans,(abs(k-t)+t)*x+(i-1)*y);
sur[i]=min(sur[i-1]+a[n-i+1],0ll);
}
cout<<Ans;
return 0;
}
标签:long i++ define can src har main scan mamicode
原文地址:https://www.cnblogs.com/yzxverygood/p/11612304.html