标签:otn 接口 contain 构造 border spel last idt 继承
关键字 | 样品方法 | SQPL片段 | 原生SQL | 备注 |
And | findPersonByLastNameAndFirstName(String lastName,String firstName) | ...where x.lastName = 1? and x.firstName = 2? | ...where lastName = 1? and firstName = 2? | 两个字段的&操作 |
Or | ||||
Is、Equals | ||||
Between | ||||
LessThan | ||||
LessThanEqual | ||||
GreaterThan | ||||
GreaterThanEqual | ||||
After | ||||
Before | ||||
isNull、Null | ||||
isNotNull、NotNull | ||||
Like | ||||
NotLike | ||||
StartingWith | ||||
EndingWith | ||||
Containing | ||||
OrderBy | ||||
Not | ||||
In | ||||
NotIn | ||||
True | ||||
False | ||||
IgnoreCase |
标签:otn 接口 contain 构造 border spel last idt 继承
原文地址:https://www.cnblogs.com/chaoyou/p/11698482.html