标签:int() tail code asc 函数参数 back fun 对象数组 调用函数
概述
Array.map() 方法返回一个新数组,数组中的元素为原始数组元素调用函数处理后的值,同时不会改变原来的数组。
用法
Array.map(callback);
示例
//简单数组 const arr = [1, 3, 4, 5, 6, 7, 8, 10]; const cube = (num) => { return num * num; } const res = arr.map(cube);//[ 1, 9, 16, 25, 36, 49, 64, 100 ] // or const res = arr.map((num)=>{ return num * num; }) //[ 1, 9, 16, 25, 36, 49, 64, 100 ] //对象数组和构造器 const OjbArray = [{ name: ‘a‘, age: 18, isLikeEat: true, isLikeSleep: true }, { name: ‘b‘, age: 19, isLikeEat: true, isLikeSleep: true }, { name: ‘c‘, age: 22, isLikeEat: true, isLikeSleep: true }]; const Person = (target) => { return { name: target.name || ‘default‘, age: target.age || 18, _eat: function() { console.log(target.isLikeEat ? ‘i like eat‘ : ‘i dont like eat‘); }, _sleep: function() { console.log(target.isLikeSleep ? ‘i like sleep‘ : ‘i dont like sleep‘) } } } let newPersons = OjbArray.map(Person); console.log((newPerso// [ { name: ‘a// age: 18, // _eat: [Function: _eat], // _sleep: [Function: _sleep] }, // { name: ‘b‘, // age: 19, // _eat: [Function: _eat], // _sleep: [Function: _sleep] }, // { name: ‘c‘, // age: 22, // _eat: [Function: _eat], // _sleep: [Function: _sleep] } ]
注意 ??
当和parseInt()函数配合使用 将字符转成数字的时候,可直接
[‘1‘, ‘2‘].map(str => parseInt(str)); //or [‘1‘, ‘2‘].map(Number)
本质上是用元素作为函数参数去调用函数,所以无需加上参数
//这种写法是错误的 const arr = [1, 3, 4, 5, 6, 7, 8, 10]; const cube = (num) => { return num * num; } const res = arr.map(cube(num))
原文链接:https://blog.csdn.net/ruffaim/article/details/82260280
标签:int() tail code asc 函数参数 back fun 对象数组 调用函数
原文地址:https://www.cnblogs.com/planetwithpig/p/11733281.html