标签:using oid ima code 代码 com 文件 iostream https
地址 https://algospot.com/judge/problem/read/BOARDCOVER
解法
DFS 最近似乎在简单DFS上花费太多时间了
首先扫描地图 统计可覆盖的元素个数 如果不是3的倍数 那肯定不能覆盖完全 返回0
然后进行DFS 尝试各种覆盖办法 一共12种(由于必须覆盖完所有元素 就规定从左上角开始覆盖,其实可以只有四种覆盖办法)
每次DFS结束则覆盖方法增加1种 尝试所有覆盖方式后 函数也返回
注意需要寻找每次下一个尝试的覆盖点 规定从左上角开始找起
代码
// 11111111111111.cpp : 此文件包含 "main" 函数。程序执行将在此处开始并结束。 // #include <iostream> #include <vector> using namespace std; const int N = 30; char gmap[N][N]; int loop; int ans = 0; int n, m; struct board { int x1, y1; int x2, y2; int x3, y3; }; vector<struct board> fillBoad= { {0,0, -1,0, 0,-1}, {0,0, 1,0, 0,-1}, {0,0, -1,0, 0,1}, {0,0, 1,0, 0,1}, {0,0, 1,0, 1,-1}, {0,0, -1,0, -1,-1}, {0,0, 1,0, 1,1}, {0,0, -1,0, -1,1}, {0,0, 0,1, -1,1}, {0,0, 0,1, 1,1}, {0,0, 0,-1, 1,-1}, {0,0, 0,-1, -1-1}, }; bool CheckXY(int x1, int y1, int x2, int y2, int x3, int y3) { if (x1 < 0 || y1 < 0 || x2 < 0 || y2 < 0 || x3 < 0 || y3 < 0) return false; if (x1 >= n || x2 >= n || x3 >= n || y1 >= m || y2 >= m || y3 >= m) return false; if (gmap[x1][y1] == ‘#‘ || gmap[x2][y2] == ‘#‘ || gmap[x3][y3] == ‘#‘) return false; return true; } void DFS(int x, int y,int needfill) { if (needfill == 0) { ans++; return; } for (; x < n; x++) { for ( y = 0; y < m; y++) { if (gmap[x][y] == ‘.‘) goto FIND; } } FIND: for (int i = 0; i < 12; i++) { int newx1 = x + fillBoad[i].x1; int newy1 = y + fillBoad[i].y1; int newx2 = x + fillBoad[i].x2; int newy2 = y + fillBoad[i].y2; int newx3 = x + fillBoad[i].x3; int newy3 = y + fillBoad[i].y3; if (CheckXY(newx1, newy1, newx2, newy2, newx3,newy3)) { gmap[newx1][newy1] = ‘#‘; gmap[newx2][newy2] = ‘#‘; gmap[newx3][newy3] = ‘#‘; needfill -= 3; int p = x; int q = y; for (; p < n; p++) { for ( q = 0; q < m; q++) { if (gmap[p][q] == ‘.‘) goto FIND1; } } FIND1: DFS( p,q, needfill); needfill += 3; gmap[newx1][newy1] = ‘.‘; gmap[newx2][newy2] = ‘.‘; gmap[newx3][newy3] = ‘.‘; } } return; } int main() { cin >> loop; while (loop--) { cin >> n >> m; memset(gmap,0,N*N); ans = 0; int count = 0; for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { cin >> gmap[i][j]; if (gmap[i][j] == ‘.‘) count++; } } if (count % 3 != 0){ cout << 0 << endl; continue; } DFS(0,0,count); cout << ans << endl; } return 0; }
ac
标签:using oid ima code 代码 com 文件 iostream https
原文地址:https://www.cnblogs.com/itdef/p/11737207.html