标签:job -o node 复制 tle server 多个 场景 for
1.浅拷贝:
将原对象或原数组的引用直接赋给新对象,新数组,新对象/数组只是原对象的一个引用;
2.深拷贝:
创建一个新的对象和数组,将原对象的各项属性的“值”(数组的所有元素)拷贝过来,是“值”而不是“引用”;
使用深拷贝的场景:
1.for循环遍历数组; var array = [1, 2, 3, 4, 5]; function copy(array) { var newArray = [] for (var i = 0; i < array.length; i++) { newArray.push(array[i]); } return newArray; } var copyArray = copy(array); copyArray[0] = 100; console.log(array); // [ 1, 2, 3, 4, 5 ] console.log(copyArray); // [ 100, 2, 3, 4, 5 ] 2.for in遍历数组; var array = [1, 2, 3, 4, 5]; function copy(array) { var newArray = [] for (var i in array) { newArray.push(array[i]); } return newArray; } var copyArray = copy(array); copyArray[0] = 100; console.log(array); // [ 1, 2, 3, 4, 5 ] console.log(copyArray); // [ 100, 2, 3, 4, 5 ] 3.silce(); //当slice()不带任何参数的时候,默认返回一个长度和原数组相同的新数组 注意:利用slice();方法不改变原数组的特性 var array = [1, 2, 3, 4, 5]; var copyArray = array.slice(); copyArray[0] = 100; console.log(array); // [1, 2, 3, 4] console.log(copyArray); // [100, 2, 3, 4] 4.concat(); //用于连接两个或多个数组。( 该方法不会改变现有的数组,而仅仅会返回被连接数组的一个副本。) var array = [1, 2, 3, 4, 5]; var copyArray = array.concat(); copyArray[0] = 100; console.log(array); // [1, 2, 3, 4] console.log(copyArray); // [100, 2, 3, 4];
1.直接遍历; var obj = { name: "admin", age: 18, sex: 0 } var obj2 = {}; for (var i in obj) { obj2[i] = obj[i]; } obj2.name = "root"; console.log(obj); //{ name: "admin", age: 18, sex: 0 } console.log(obj2); //{ name: "root", age: 18, sex: 0 } 2.Object.assign:用于对象的合并,将源对象(source)的所有可枚举属性,复制到目标对象(target),并返回合并后的target //ES6提供; 用法: Object.assign(target, source1, source2); var obj = { name: ‘这是初始name‘, job: ‘这是初始job‘, age: 18 } var copyObj = Object.assign({}, obj); copyObj.name = ‘这是拷贝后的name‘; console.log(obj); // { name: "这是初始name", job: "这是初始job", age: 18 } console.log(copyObj); // { name: "这是拷贝后的name", job: "这是初始job", age: 18 }
var array = { name: "obj-1", profn: function(n) { return n * 2; }, proArr: [1, 2, 3, 4], proObj: { a: "aa", b: "bb" }, profn2: function(m, n) { return m + n; }, proObj2: { pro1: "1212", pro2: { qq: "qq", ww: "ww" } } }; var copyArray = JSON.parse(JSON.stringify(array)) copyArray.name = "101"; console.log(array); // console.log(copyArray); //
var obj1 = { name: "obj-1", profn: function(n) { return n * 2; }, proArr: [1, 2, 3, 4], proObj: { a: "aa", b: "bb" }, profn2: function(m, n) { return m + n; }, proObj2: { pro1: "1212", pro2: { qq: "qq", ww: "ww" } } } console.log(obj1); //{ name: "obj-1", profn: profn(), proArr: (4) […], proObj: {…}, profn2: profn2(), proObj2: {…} } function copyFn(obj) { if (obj == null) { return null } var result = Array.isArray(obj) ? [] : {}; for (var key in obj) { if (obj.hasOwnProperty(key)) { if (typeof obj[key] === ‘object‘) { result[key] = copyFn(obj[key]); // 如果是对象,再次调用该方法自身 } else { result[key] = obj[key]; } } } return result; } var obj2 = copyFn(obj1); obj2.name = ‘Edited‘; console.log(obj1); //{ name: "obj-1", profn: profn(), proArr: (4) […], proObj: {…}, profn2: profn2(), proObj2: {…} } console.log(obj2); //{ name: "Edited", profn: profn(), proArr: (4) […], proObj: {…}, profn2: profn2(), proObj2: {…} }
标签:job -o node 复制 tle server 多个 场景 for
原文地址:https://www.cnblogs.com/jwyblogs/p/11781109.html