剑指offer树的子结构python

# -*- coding:utf-8 -*-
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None
class Solution:
    def HasSubtree(self, pRoot1, pRoot2):
        # write code here
        result = False
        if pRoot1 and pRoot2:
            if pRoot1.val == pRoot2.val:
                result = self.isSubtree(pRoot1,pRoot2)
            if not result and pRoot1.left:
                result = self.isSubtree(pRoot1.left,pRoot2)
            if not result and pRoot2.right:
                result = self.isSubtree(pRoot1.right,pRoot2)
        return result
    
    def isSubtree(self,p1,p2):
        if not p2:
            return True
        if not p1:
            return False
        if p1.val != p2.val:
            return False
        check_left = self.isSubtree(p1.left, p2.left)
        check_right = self.isSubtree(p1.right,p2.right)
        return check_left and check_right