码迷,mamicode.com
首页 > 编程语言 > 详细

java判断两集合是否相同以及求取交集,并集,差集

时间:2019-11-04 13:45:45      阅读:81      评论:0      收藏:0      [点我收藏+]

标签:style   pre   info   cat   rem   div   数据   用户   hash   

业务中用时需要判断两集合是否相同,所有提供一个工具方法,使用set集合的特性(元素唯一):

private Map<String,Set<Integer>> getCategoryApiId(Set<Integer> oldAuthSet , Set<Integer> newAuthSet){
        Map<String,Set<Integer>> categoryApiId = new HashMap();
        if (oldAuthSet!=null&&newAuthSet!=null){
            //首先判断两个集合是否一致
            if (oldAuthSet.size()==newAuthSet.size()){
                Set<Integer> tempSet = new HashSet<Integer>();
                tempSet.addAll(oldAuthSet);
                tempSet.addAll(newAuthSet);
                if (tempSet.size()==oldAuthSet.size()){
                    categoryApiId =null;//未增加api个数
                    logger.info("未新增和删除api");
                }else{
                    //1:交集;2:a-b的差集;3:并集
                    Set<Integer> apiSet1 = getApiSet(oldAuthSet, newAuthSet, 1);
                    Set<Integer> deleteAuthSet = getApiSet(oldAuthSet, apiSet1, 2);
                    Set<Integer> insertAuthSet = getApiSet(newAuthSet,oldAuthSet , 2);//获取新增的apiId
                    logger.info("删除的api:"+deleteAuthSet);
                    logger.info("新增的api:"+insertAuthSet);
                    categoryApiId.put("insertApi",insertAuthSet);
                    categoryApiId.put("datele",deleteAuthSet);
                }
            }else{
                //1:交集;2:a-b的差集;3:b-a的差集;4:并集
                Set<Integer> apiSet1 = getApiSet(oldAuthSet, newAuthSet, 1);
                Set<Integer> deleteAuthSet = getApiSet(oldAuthSet, apiSet1, 2);//获取删除的apiId
                Set<Integer> insertAuthSet = getApiSet(newAuthSet, oldAuthSet, 2);//获取新增的apiId
                logger.info("删除的api:"+deleteAuthSet);
                logger.info("新增的api:"+insertAuthSet);
                categoryApiId.put("insertApi",insertAuthSet);
                categoryApiId.put("datele",deleteAuthSet);
            }
        }else{
            if (oldAuthSet==null&&newAuthSet!=null){    //全是新增api
                logger.info("首次新增授权api");
                categoryApiId.put("insertApi",newAuthSet);
            }else if (oldAuthSet!=null&&newAuthSet==null){  //未修改用户授权api的数据
                logger.info("未增加新授权的api");
                categoryApiId.put("datele",oldAuthSet);
            }else if (oldAuthSet==null&&newAuthSet==null){
                logger.info("已授权api和新增授权api都为空");
                categoryApiId =null;
            }
        }
        return categoryApiId;
    }

private Set<Integer>  getApiSet(Set<Integer> oldAuthSet, Set<Integer> newAuthSet,int flag) {
        Set<Integer> result = new HashSet<Integer>();
        if(flag==1){ //求交集
            result.clear();
            result.addAll(oldAuthSet);
            result.retainAll(newAuthSet);
        }else if(flag==2){ //求差集
            result.clear();
            result.addAll(oldAuthSet);
            result.removeAll(newAuthSet);
        } else if (flag==3){ //求并集
            result.clear();
            result.addAll(oldAuthSet);
            result.addAll(newAuthSet);
        }
        return result;
    }

 

java判断两集合是否相同以及求取交集,并集,差集

标签:style   pre   info   cat   rem   div   数据   用户   hash   

原文地址:https://www.cnblogs.com/zyanrong/p/11791508.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!