标签:break res bsp push nic div i++ for 网络最大流
void add_dinic(int u, int v) { e[++cnt].v = v; e[cnt].w = 0; e[cnt].nxt = head[u]; head[u] = cnt; } int dfs_dinic(int x, int flow) { if (x == ed) return flow; int res = 0; for (int i = now[x]; i != -1; i = e[i].nxt) { int v = e[i].v; if (d[v] + 1 == d[x] && e[i].w > 0) { int k = dfs_dinic(v, min(e[i].w, flow)); res += k; flow -= k; e[i].w -= k; e[i ^ 1].w += k; if (!flow) break; } } return res; } bool bfs_dinic() { memset(d, 0, sizeof(d)); queue<int>q; q.push(ed); d[ed] = 1; while (!q.empty()) { int u = q.front(); q.pop(); for (int i = head[u]; i != -1; i = e[i].nxt) { int v = e[i].v; if (!d[v] && e[i ^ 1].w > 0) { q.push(v); d[v] = d[u] + 1; } } } return d[st] > 0; } int dinic() { int flow = 0; while (bfs_dinic()) { for (int i = 0; i <= ed; i++) now[i] = head[i]; flow += dfs_dinic(st, INF); } return flow; }
标签:break res bsp push nic div i++ for 网络最大流
原文地址:https://www.cnblogs.com/thjkhdf12/p/11823731.html