python练习：字典value值排序，key值排序

#字典value值排序，key值排序
from random import *
dict1 = {x:randint(5,12) for x in "aijwt"}
dict2 = {randint(5,12):y for y in "aibjwte"}
print (‘dict1:‘,dict1)
print (‘dict2:‘,dict2)

print ("将字典按value倒序显示，办法（collections的Counter）：")
from collections import Counter
dict11 = Counter(dict1).most_common()                   #转为列表
dict22 = Counter(dict2).most_common()                   #转为列表
print(‘dict1按value倒序显示:‘,dict(dict11))              #转为字典显示
print(‘dict2按value倒序显示:‘,dict(dict22))              #转为字典显示


print ("将字典按key正序显示")
dict12 = list(dict1.items())
dict12.sort(key=lambda x:x[0])    #按照列表中元组元素的的第一个元素排序
print(‘dict1按key正序显示:‘,dict12)


print ("将字典按value正序显示")
dict13 = list(dict1.items())
dict13.sort(key=lambda x:x[1])    #按照列表中元组元素的的第二个元素排序
print(‘dict1按value正序显示:‘,dict13)


print(‘\n==========================分割一下=================================\n‘)
a1= list(dict1)                             #字典key转为列表
a2= list(dict1.items())                     #字典元素转为列表
a3= [i for i in dict1.items()]              #字典元素转为列表

print(‘dict1:‘,dict1)
print(‘list(dict1) :‘,a1)
print(‘list(dict1.items()) :‘,a2)
print(‘[i for i in dict1.items()]:‘,a3)


#列表转为字典
print(dict(a3))

dict1: {‘a‘: 7, ‘i‘: 7, ‘j‘: 7, ‘w‘: 11, ‘t‘: 11}
dict2: {12: ‘j‘, 5: ‘i‘, 8: ‘b‘, 9: ‘w‘, 7: ‘t‘, 11: ‘e‘}
将字典按value倒序显示，办法（collections的Counter）：
dict1按value倒序显示: {‘w‘: 11, ‘t‘: 11, ‘a‘: 7, ‘i‘: 7, ‘j‘: 7}
dict2按value倒序显示: {9: ‘w‘, 7: ‘t‘, 12: ‘j‘, 5: ‘i‘, 11: ‘e‘, 8: ‘b‘}
将字典按key正序显示
dict1按key正序显示: [(‘a‘, 7), (‘i‘, 7), (‘j‘, 7), (‘t‘, 11), (‘w‘, 11)]
将字典按value正序显示
dict1按value正序显示: [(‘a‘, 7), (‘i‘, 7), (‘j‘, 7), (‘w‘, 11), (‘t‘, 11)]

==========================分割一下=================================

dict1: {‘a‘: 7, ‘i‘: 7, ‘j‘: 7, ‘w‘: 11, ‘t‘: 11}
list(dict1) : [‘a‘, ‘i‘, ‘j‘, ‘w‘, ‘t‘]
list(dict1.items()) : [(‘a‘, 7), (‘i‘, 7), (‘j‘, 7), (‘w‘, 11), (‘t‘, 11)]
[i for i in dict1.items()]: [(‘a‘, 7), (‘i‘, 7), (‘j‘, 7), (‘w‘, 11), (‘t‘, 11)]
{‘a‘: 7, ‘i‘: 7, ‘j‘: 7, ‘w‘: 11, ‘t‘: 11}

Process finished with exit code 0