python的顺序结构、选择结构、循环结构的练习代码

#判断类型
from os import name

#print(100,type(100))
#print(‘100‘,type(‘100‘))

#Python中只要被引号引起来的都是字符串


#用户交互
‘‘‘name = input(‘请输入您的姓名：‘)
age = input(‘请输入您的年龄：‘)
print(‘您的信息：‘+ age,name,type(name))

#第一种：必走
if True:
    print(111)
#第二种：二选一
if 4 > 3 :
    print(‘我请你喝酒‘)
else :
    print(‘算了吧‘)
#第三种：多选一
num = int(input(‘请您输入：‘))
if num == 1 :
    print(‘我请您吃饭‘)
elif num == 2 :
    print(‘我请你去洗脚‘)
elif num == 3 :
    print(‘新开一家，走，去看看‘)
else :
    print(‘今天保重身体，保温杯里泡点枸杞‘)

#if嵌套
name =input("输入姓名：")
age = input("输入年龄：")
if name == ‘李雪‘:
    if age == ‘21‘:
        print(‘niao‘)
    else:
        print(‘hello‘)
else:
    print(‘maodan‘)

#while
count = 1
flag = True

while flag :
    print(count)
    count +=1
    if count >100 :
        flag = False

count = 1

while count <= 100 :
    print(count)
    count += 1

count = 1
sum = 0
while count <= 100:
    break
    sum +=count
    count += 1
print(sum)

#break 终止循环
print(‘eee‘)
while True:
    print(‘222‘)
    print(‘3333‘)
    print(‘444444‘)
    print(333333333)
    break
    print(‘woaini‘)
    print(‘eeeeeeeeee4‘)
    print(‘qunabushiwodepengyouma,wo buquedinga,zenmebanne,wodeairenmen‘)
print(‘aaa‘)
#continue   遇到continue就返回，它见底了，返回之
count =1
while count <= 20:
    print(count)
    continue
    count +=1‘‘‘

count = 0
while count <= 100:
    count += 1
    if count > 5 and count < 95:
        continue
    print("loop ", count)

print("-----out of while loop ------")