python爬取猫眼电影的Top100

 1  for cate,score in zip(Movie_name,Movie_Score1):
 2         data={}
 3         movie_name1 = cate.find(‘a‘).text.strip(‘\n‘)
 4         data[‘title‘]=movie_name1
 5         movie_actor = cate.find_all("p")[1].text.replace("\n"," ").strip()
 6         data[‘actors‘]=movie_actor
 7         movie_time=cate.find_all("p")[2].text.strip(‘\n‘).strip()
 8         data[‘data‘]=movie_time
 9         movie_score1=score.find_all("i")[0].string
10         movie_score2=score.find_all("i")[1].string
11         movie_score=movie_score1+movie_score2
12         data[‘score‘] = movie_score
13         name = movie_name1 + "\t"+movie_actor+"\t" + movie_time+"\t"+movie_score
14         DATA.append(name)
15         with open(‘Movie1.txt‘, ‘a+‘) as f:
16             f.write("\n{}".format(name))

1   for datas in DATA:
2         datas=datas.split(‘\t‘)#因为我之前解析字段拼接的时候就是采用\t分割
3         print(len(datas))
4         print(datas)
5         for j in range(len(datas)):#列表中的每一项都包含按照\t分割的字段
6             print(j)
7             sheet1.write(i, j, datas[j])
8         i = i + 1
9     f.save("d.xls")  # 保存文件