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【算法日常】判断环形链表

时间:2019-12-08 23:17:56      阅读:149      评论:0      收藏:0      [点我收藏+]

标签:快慢指针   int   查询   def   记录   problem   time   节点   link   

环形链表

题目来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/linked-list-cycle-ii

技术图片

目前考虑到两种解法,但都需要辅助空间, 第一种 O(n) 第二种 O(1)

第一种 借助辅助字典进行判断

将走过的节点都记录在字典中,通过查询字典的key值是否存在来确定是否有环
时间复杂度为 O(n) , 空间复杂度为 O(n)

代码如下:

# -*- coding: utf-8 -*-
# @Author   : xaohuihui
# @Time     : 19-12-6
# @File     : detect_cycled.py
# Software  : study

"""
检测环形链表
"""

class ListNode:
    def __init__(self, x):
        self.val = x
        self.next = None

def has_cycle(head: ListNode) -> bool:
    dict_node = dict()
    i = 0
    if head and head.next:
        while head and head.next:
            id_head = str(id(head))
            if dict_node.get(id_head) is None:
                dict_node[id_head] = i
            else:
                return True
            i += 1
            head = head.next
        return False
    else:
        return False

if __name__ == ‘__main__‘:
    # head=[3,2,0,4] pos= 1
    node1 = ListNode(3)
    node2 = ListNode(2)
    node3 = ListNode(0)
    node4 = ListNode(4)

    node1.next = node2
    node2.next = node3
    node3.next = node4
    node4.next = node2

    print(has_cycle(node1))

输出如下:

True

第二种解法 快慢指针

# -*- coding: utf-8 -*-
# @Author   : xaohuihui
# @Time     : 19-12-6
# @File     : detect_cycled.py
# Software  : study

"""
检测环形链表
"""

class ListNode:
    def __init__(self, x):
        self.val = x
        self.next = None

# 第二种解法
def has_cycle(head: ListNode) -> bool:
    if head and head.next:
        fast = slow = head
        while fast and fast.next:
            slow = slow.next
            fast = fast.next.next
            if fast == slow:
                return True

    else:
        return False

if __name__ == ‘__main__‘:
    # head=[3,2,0,4] pos= 1
    node1 = ListNode(3)
    node2 = ListNode(2)
    node3 = ListNode(0)
    node4 = ListNode(4)

    node1.next = node2
    node2.next = node3
    node3.next = node4
    node4.next = node2

    print(has_cycle(node1))

输出结果

True

【算法日常】判断环形链表

标签:快慢指针   int   查询   def   记录   problem   time   节点   link   

原文地址:https://blog.51cto.com/14612701/2457002

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