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【leetcode】1287. Element Appearing More Than 25% In Sorted Array

时间:2019-12-15 10:38:07      阅读:108      评论:0      收藏:0      [点我收藏+]

标签:leetcode   for   out   ons   lin   int   return   代码   ring   

题目如下:

Given an integer array sorted in non-decreasing order, there is exactly one integer in the array that occurs more than 25% of the time.

Return that integer.

Example 1:

Input: arr = [1,2,2,6,6,6,6,7,10]
Output: 6

Constraints:

  • 1 <= arr.length <= 10^4
  • 0 <= arr[i] <= 10^5

解题思路:最直接的方法是统计每个元素出现的次数。

代码如下:

class Solution(object):
    def findSpecialInteger(self, arr):
        """
        :type arr: List[int]
        :rtype: int
        """
        dic = {}
        res = 0
        for i in arr:
            dic[i] = dic.setdefault(i,0) + 1
            if dic[i] > len(arr)/4:
                res = i
                break
        return res

 

【leetcode】1287. Element Appearing More Than 25% In Sorted Array

标签:leetcode   for   out   ons   lin   int   return   代码   ring   

原文地址:https://www.cnblogs.com/seyjs/p/12041875.html

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